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प्रश्न
If 4, x1, x2, x3, 28 are in AP then x3 = ?
विकल्प
19
23
22
Cannot be determined
MCQ
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उत्तर
22
Explanation:
Given AP is 4, x1, x2, x3, 28.
Clearly, a = 4 and T5 = 28.
Now, T5 = 28
⇒ a + 4d = 28
⇒ 4 + 4d = 28
⇒ 4d = 24
⇒ d = 6
∴ x3 = T4
= (a + 3d)
= (4 + 3 × 6)
= 22
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