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Question
An AP 5, 12, 19, ... has 50 terms. Its last term is ______.
Options
343
353
348
362
MCQ
Fill in the Blanks
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Solution
An AP 5, 12, 19, ... has 50 terms. Its last term is 348.
Explanation:
The sequence is an AP with first term a = 5 and common difference d = 12 – 5 = 7.
Use the nth-term formula
Tn = a + (n – 1)d
For n = 50:
T50 = 5 + 49 × 7
= 5 + 343
= 348
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