Question

An AP 5, 12, 19, ... has 50 terms. Its last term is ______.

पर्याय

• 343

• 353

• 348

• 362

Answer 1

An AP 5, 12, 19, ... has 50 terms. Its last term is 348.

Explanation:

The sequence is an AP with first term a = 5 and common difference d = 12 – 5 = 7.

Use the nth-term formula

T_n = a + (n – 1)d

For n = 50:

T₅₀ = 5 + 49 × 7 

= 5 + 343

= 348