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Question
The sum of first 40 positive integers divisible by 6 is ______.
Options
2460
3640
4920
4860
MCQ
Fill in the Blanks
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Solution
The sum of first 40 positive integers divisible by 6 is 4920.
Explanation:
The numbers 6, 12, 18, ..., 6 × 40 = 240 form an AP with n = 40, a = 6 and last term l = 240.
Use `S_n = n/2 (a + l)`:
`S_40 = 40/2 xx (6 + 240)`
= 20 × 246
= 4920
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