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Question
How many terms are there in the AP 41, 38, 35, ...,8?
Sum
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Solution
In the given AP, a = 41 and d = (38 – 41) = –3
Suppose that there are n terms in the given AP.
Then Tn = 8
⇒ a + (n – 1) d = 8
⇒ 41 + (n – 1) × (–3) = 8
⇒ 44 – 3n = 8
⇒ 3n = 36
⇒ n = 12
Hence, there are 12 terms in the given AP.
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