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Question
Find the middle term of the AP 6, 13, 20, ..., 216.
Sum
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Solution
The given AP is 6, 13, 20, .., 216.
First term, a = 6
Common difference, d = 13 – 6 = 7
Suppose these are n terms in the given AP. Then,
an = 216
⇒ 6 + (n – 1) × 7 = 216 ...[an = a + (n – 1)d]
⇒ 7(n – 1) = 216 – 6 = 210
⇒ `n - 1 = 210/7 = 30`
⇒ n = 30 + 1 = 31
Thus, the given AP contains 31 terms,
∴ Middle term of the given AP
= `((31 + 1)/2)`th term
= 16th term
= 6 + (16 – 1) × 7
= 6 + 105
= 111
Hence, the middle term of the given AP is 111.
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