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Question
Find the 15th term of the AP –40, –15, 10, 35,....
Sum
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Solution
The given AP is –40, –15, 10, 35,....
First term, a = –40
Common difference, d = –15 – (–40) = 25
nth term of the AP,
an = a + (n – 1)d
= –40 + (n – 1) × 25
∴ 15th term of the AP,
a15 = –40 + (15 – 1) × 25
= –40 + 350
= 310
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