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Magnetic Field on the Axis of a Circular Current Loop

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Estimated time: 1 minutes
CBSE: Class 12

Formula: Magnetic Field on the Axis of a Circular Loop

\[\vec{B}=\frac{\mu_0IR^2}{2(x^2+R^2)^{3/2}}\hat{i}\]

Where:

  • I = current
  • R = radius of loop
  • x = distance from centre along axis
  • μ0 = permeability of free space

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