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Inductance - Mutual Inductance

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Estimated time: 20 minutes
CBSE: Class 12

Introduction

Every time you charge your phone wirelessly, use a transformer, or start a car's ignition, mutual inductance is at work. It is the fundamental principle behind transformers, induction cooktops, RFID cards, and wireless charging pads.

When two coils are placed near each other, a changing current in one coil produces a changing magnetic flux, which links with the neighbouring coil and induces an EMF in it — even without physical contact.

CBSE: Class 12
Maharashtra State Board: Class 11

Definition: Mutual Inductance

The property of two coils by which a change in current in one coil induces an emf in the other coil — equal to the magnetic flux linked with one circuit per unit current in the other, or the value of induced emf produced in the secondary circuit per unit rate of change in current in the primary circuit — is called mutual inductance.

OR

Mutual Inductance (M) of a pair of coils is defined as the ratio of the total magnetic flux linkage in the secondary coil to the current in the primary coil that produces it.

CBSE: Class 12

Definition: Coefficient of Coupling

The coefficient of coupling K between two coils is the fraction of the total magnetic flux produced by one coil that links with the other coil.

CBSE: Class 12
Maharashtra State Board: Class 11

Formula: Mutual Inductance

N2​ϕ21 ​∝ I1​ ⟹ N2​ϕ21​ = M ⋅ I1

Therefore:

M = \[\frac{N_{2}\phi_{21}}{I_{1}}\]
CBSE: Class 12

Formula: Coefficient of Coupling

M = K\[\sqrt {L_1L_2}\]

Where:

  • L1, L2​ = Self-inductances of coil 1 and coil 2
  • K = Coefficient of coupling (dimensionless, no units)
  • Range: 0 ≤ K ≤ 1

Therefore:

M ≤ \[\sqrt {L_1​L_2}\]​​

CBSE: Class 12

EMF Form of Mutual Inductance

From Faraday's Second Law, the EMF induced in the secondary coil is:

\[e_2=-N_2\frac{d\phi_{21}}{dt}=-M\frac{dI_1}{dt}\]

If the rate of change of current in the primary is 1 A/s and the induced EMF in the secondary is 1 V, then M = 1 H (one Henry).

CBSE: Class 12

SI Unit and Dimensions

Property Value
SI Unit Henry (H)
Dimensional Formula \[\left[ML^{2}T^{-2}A^{-2}\right]\] (same as self-inductance)
Other Units mH (millihenry), μH (microhenry)
Named after Joseph Henry (American scientist)

1 H = 1 V·s/A = 1 Wb/A

CBSE: Class 12

Reciprocity Theorem

Statement: The mutual inductance of coil 1 with respect to coil 2 equals the mutual inductance of coil 2 with respect to coil 1.

M12 = M21 = M

This is called the Reciprocity Theorem of Mutual Inductance.

Implication: It does not matter which coil drives the current — the mutual inductance M between the pair is always the same property of the system, not just one coil.youtube

CBSE: Class 12

Factors Affecting Mutual Inductance

The value of M between two coils depends on the following:

  • Number of turns N1​ and N2​ — M increases as turns increase (M ∝ N1N2)
  • Size and geometry of the coils — larger cross-sectional area → more flux linkage → larger M
  • Distance between coils — as distance increases, M decreases (less flux links the secondary)
  • Relative orientation — M is maximum when coils are coaxial (same axis); M = 0 when coil axes are perpendicular to each other
  • Permeability of the core medium (μr\mu_rμr​) — winding coils on a soft iron core greatly increases M
  • Coupling factor K — quantifies how efficiently flux is shared between the coils
CBSE: Class 12

Derivation: Mutual Inductance of Two Coaxial Solenoids

Setup:

  • Solenoid S₁ (primary): length l, N1​ turns, n1 = N1/l turns/m, radius r1 (larger)
  • Solenoid S₂ (secondary): N2​ turns, n2 = N2/l​ turns/m, radius r2 (smaller, wound inside S₁)
  • Current I1​ passed through S₁

Step 1: Magnetic field inside S₁:

  • B1 = μ0n1I1

Step 2: Flux through each turn of S₂ (area = \[\pi r_2^2\], the smaller radius):

  • ϕ21 = B1 ⋅ \[\pi r_2^2\] = μ0n1I1\[\pi r_2^2\]

Step 3: Total flux linkage of S₂:

  • N2ϕ21 = μ0​n1​n2​l ⋅ \[\pi r_2^2\] ⋅ I1​

Step 4: Mutual Inductance:

  • M21 = μ0n1n2\[\pi r_2^2,\]l

Or equivalently (using N1 = n1l and N2 = n2l):

  • M = ​\[\frac{\mu_0N_1N_2A}{l}\]

where A = \[\pi r_2^2\]​ (cross-sectional area of the inner solenoid).

Similarly: M12 = μ0n1n2\[\pi r_2^2\]l, confirming Reciprocity: M12 = M21 = M.

CBSE: Class 12

Special Case — Two Concentric Coplanar Circular Coils

For a small coil of radius r1​ placed at the centre of a large coil of radius r2​ (where r1 ≪ r2​):

M = \[\frac{\mu_0\pi r_1^2}{2r_2}\]

CBSE: Class 12

Example

Two concentric circular coils are placed with the same centre and axis. The small coil has radius r1=​ and the large coil has radius r2​, with r1 ≪ r2​.

A current I2​ is passed through the outer large coil. This creates a magnetic field at its centre:

  • B2 = \[\frac{\mu_0I_2}{2r_2}\]

Since the inner coil is very small compared to the outer coil, this field B2 can be assumed uniform across the entire area of the inner coil. This is the key approximation in the problem.

The magnetic flux passing through the inner small coil is then:

  • Φ1 = \[\pi r_1^2\cdot B_2=\frac{\mu_0\pi r_1^2I_2}{2r_2}\]

By definition, Φ1 = M12 ⋅ I2. Comparing both sides gives the mutual inductance:

  • M = \[\frac{\mu_0\pi r_1^2}{2r_2}\]

Finally, by the Reciprocity Theorem, M12 = M21 = M, so this single value describes the mutual inductance of the entire arrangement regardless of which coil carries the current.

CBSE: Class 12

Real-World Applications

Application How (M) Is Used
Transformer Steps up or steps down voltage using tightly coupled coils (k ≈ 1).
Wireless charging Loosely coupled coils transfer energy without physical contact.
Induction cooktop Changing the current in the cooktop coil induces current in the cookware.

Video Tutorials

We have provided more than 1 series of video tutorials for some topics to help you get a better understanding of the topic.

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Shaalaa.com | Electromagnetic Induction part 15 (Inductance)

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Electromagnetic Induction part 15 (Inductance) [00:14:36]
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