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Maharashtra State BoardSSC (English Medium) 10th Standard

Magnetic force

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Estimated time: 16 minutes
CBSE: Class 12
Maharashtra State Board: Class 11

Definition: Magnetic Force

The force experienced by a moving charge in the presence of a magnetic field, which depends on charge q, velocity v and magnetic field B, and which is opposite in direction on a negative charge compared to a positive charge, is called the magnetic force.

CBSE: Class 12

Definition: Lorentz Force

When both electric and magnetic fields act on a charge, the total force is called the Lorentz force.

Maharashtra State Board: Class 11

Formula: Magnetic Force

Vector Form: \[\vec F\] = q(\[\vec v\] × \[\vec B\])

Magnitude Form: F = qv B sin θ

Where:

  • q = charge on the particle
  • v = speed of the particle
  • B = magnetic field strength
  • θ = angle between \[\vec v\] and \[\vec B\]
CBSE: Class 12

Formula: Electric Field Due to a Point Charge

\[\vec{E}=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}\hat{r}\]

Maharashtra State Board: Class 11

Formula: Maximum Magnetic Force

Maximum magnetic force (when v ⊥ B): Fmax = qv B

CBSE: Class 12

Formula: Lorentz Force

\[\vec F\] = q(\[\vec E\] + \[\vec v\] × \[\vec B\])

Maharashtra State Board: Class 11

Law: Fleming's Left-Hand Rule

If we stretch the index finger, middle finger and thumb of the left hand mutually perpendicular to each other such that the index finger points along the direction of the magnetic field and the middle finger along the direction of current (moving charge), then the thumb represents the direction of the force F experienced by the moving charge.

CBSE: Class 12

Special Cases Table

Condition Angle θ Formula Result
Particle at rest F = 0 No magnetic force
Motion parallel to the field 0° or 180° F = qvB sinθ = 0 No magnetic force
Motion perpendicular to the field 90° F = qv B Maximum force
Motion at an angle any other angle F = qvBsin⁡θ Partial force
CBSE: Class 12

Direction of Magnetic Force

Right-Hand Rule

For a positive charge, point the fingers in the direction of velocity \[\vec v\], then curl them toward the magnetic field \[\vec B\]; the thumb gives the direction of the force.

For a negative charge, the force is in the opposite direction.

Fleming's Left-Hand Rule

When the thumb, forefinger, and middle finger of the left hand are stretched mutually perpendicular to each other:

  • The forefinger shows the magnetic field
  • The middle finger shows current
  • The thumb shows force or motion
CBSE: Class 12

Units and Meaning of Tesla

SI Unit of Magnetic Field

The SI unit of magnetic field is tesla (T).

A magnetic field of 1 tesla is defined as the field in which a charge of 1 coulomb moving with speed 1 m/s at right angles to the field experiences a force of 1 newton.

CGS Unit

  • 1 tesla = 10,000 gauss

CBSE: Class 12

Derivation

From experiments, the magnetic force on a moving charge is found to be:

  • directly proportional to charge q
  • directly proportional to speed v
  • directly proportional to field strength B
  • directly proportional to sin⁡θ

Hence,

F ∝ q
F ∝ v
F ∝ B
F ∝ sin ⁡θ

Combining all,

F ∝ qvB sin θ
F = qvB sin⁡ θ

The vector form is:

\[\vec F\] =q(\[\vec v\] × \[\vec B\])
CBSE: Class 12

Comparison: Electric Force vs Magnetic Force

Feature Electric Force Magnetic Force
Acts on Charge at rest or in motion Only moving charge
Formula F = qE F = qvB sin ⁡θ
Direction Along the electric field for a positive charge Perpendicular to both \[\vec v\] and \[\vec B\]
Work done Can do work Does no work alone
Changes Speed and direction Direction only
CBSE: Class 12

Example 1

Problem: A straight wire of mass 200 g and length 1.5 m carries a current of 2 A. It is suspended in mid-air by a uniform horizontal magnetic field B. Find B.

Concept used: Force on a current-carrying conductor: F = BIl

Solution:
For the wire to float, the upward magnetic force must equal the downward gravitational force:

mg = BIl
B = \[\frac {mg}{Il}\] = \[\frac {0.2×9.8}{2×1.5}\] = \[\frac {1.96}{3}\] = 0.65 T

Exam takeaway: Only the ratio m/l (mass per unit length) matters here, not the individual values.

CBSE: Class 12

Example 2

Problem: Magnetic field B is along the +y axis. A charged particle moves along the +x axis. Find the direction of force for (a) an electron, (b) a proton.

Concept used: Vector cross product: \[\vec F\] = q(\[\vec v\] × \[\vec B\])

Solution:
Using the right-hand rule:

\[\hat i\] × \[\hat j\] = \[\hat k\] (along +z axis)
  • For a proton (positive charge): force is along +z axis
  • For an electron (negative charge): force is along the −z axis (direction reverses for negative charge)

Exam takeaway: Always apply the right-hand rule first for a positive charge, then reverse for a negative charge.

CBSE: Class 12

Real-Life Applications

  • Motion of charged particles in a cyclotron depends on the magnetic force.
  • Electron beams in older CRT displays are controlled using electric and magnetic fields.
  • The circular motion of charged particles in many instruments is produced by the magnetic force acting as a centripetal force.

Analogy

Magnetic force acts like a sideways push that bends the path of a moving charge without pushing it forward.

CBSE: Class 12

Key Concepts

Conditions for Magnetic Force

  • The charge must be moving.
  • A magnetic field must be present.
  • The force depends on the angle between the motion and the field.

Nature of the Force

  • Magnetic force changes the direction of motion, not the speed, when only the magnetic field acts.
  • Therefore, the magnetic force does no work on the charged particle.

Video Tutorials

We have provided more than 1 series of video tutorials for some topics to help you get a better understanding of the topic.

Series 1


Series 2


Series 3


Shaalaa.com | Introduction

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Introduction [00:39:59]
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