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Flux of a Vector Field

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Estimated time: 15 minutes
CISCE: Class 12

Introduction

Flux is one of the most conceptually important yet frequently misunderstood ideas in electromagnetism. Before defining it mathematically, it helps to build intuition using a real-life analogy.

Real-Life Analogy — Water Flowing Through a Net: Imagine holding a net upright in a flowing river. The amount of water passing through the net depends on:

  • How fast the water flows (field strength)
  • The area of the net (surface area)
  • The angle at which you hold the net relative to the water flow (angle of incidence)

If you tilt the net so it is parallel to the flow, almost no water passes through. If you hold it perpendicular to the flow, maximum water passes through. This is exactly how flux behaves for electric and magnetic fields.

CISCE: Class 12

Definition: General Vector Flux

Flux of a vector field through a surface is defined as the total number of field lines passing normally through that surface. Mathematically, it is the scalar (dot) product of the field vector and the area vector.

CISCE: Class 12

Definition: Electric Flux

Electric flux (ΦE​) through a surface is the measure of the electric field lines passing through that surface.

CISCE: Class 12

Definition: Magnetic Flux

Magnetic flux (ΦB​) is the total number of magnetic field lines passing normally through a given area.

CISCE: Class 12

Formula: Flux Through an Inclined Surface

For a uniform field \[\vec F\] passing through a flat surface of area A, inclined at angle θ to the field:

Φ = \[\vec F\] ⋅ \[\vec A\] = FA cos⁡ θ

For electric flux specifically:

ΦE = \[\vec F\] ⋅ \[\vec A\] = EA cos⁡ θ
CISCE: Class 12

Formula: Flux for Non-Uniform Fields

For a non-uniform field or curved surface, flux is expressed as a surface integral:

\[\Phi_E=\int_A\vec{E}\cdot d\vec{A}\]

CISCE: Class 12

Formula: Flux in a Closed Surface

For a closed surface (used in Gauss's Law):

\[\Phi_E=\oint\vec{E}\cdot d\vec{A}=\frac{q_{enc}}{\varepsilon_0}\]

CISCE: Class 12

Special Cases

The value of flux depends critically on the angle θ\thetaθ between the field vector and the area vector (normal to the surface).

  • θ = 0° (field parallel to normal, i.e., perpendicular to surface): Flux is maximum, Φ = FA
  • θ = 90° (field parallel to surface): Flux is zero, Φ = 0
  • θ = 180° (field opposite to normal): Flux is maximum negative, Φ = −FA
CISCE: Class 12

Electric Flux vs Magnetic Flux

Feature Electric Flux (ΦE) Magnetic Flux (ΦB​)
Definition Field lines of \[\vec E\] through a surface Field lines of \[\vec B\] through a surface
Formula ΦE = EA cos ⁡θ ΦB = BA cos⁡ θ
SI Unit N m² C⁻¹ or V m Weber (Wb)
Related Law Gauss's Law of Electrostatics Faraday's Law of Electromagnetic Induction
Source Electric charges Moving charges / currents / magnets
CISCE: Class 12

SI Units & Dimensional Formula

Quantity SI Unit Dimensional Formula
Electric Flux N m² C⁻¹ or V m [ML3T−3A−1]
Magnetic Flux Weber (Wb) or T·m² [ML2T−2A−1]
CISCE: Class 12

Applications

  • Gauss's Law: Electric flux through a closed surface is directly proportional to enclosed charge — forms the basis of calculating fields for symmetric charge distributions [web:21].
  • Electromagnetic Induction: Change in magnetic flux through a coil induces an EMF (Faraday's Law) — the working principle behind generators and transformers.
  • Fluid Dynamics Analogy: Same mathematical structure used to calculate volumetric flow rate of fluids, Q = \[\vec v\] . \[\vec A\] = vA cos ⁡θ.
CISCE: Class 12

Example 1

A square surface of area 1 m² lies in the XY-plane. If \[\vec E\] = (4\[\hat i\] + 5\[\hat j\]) × 103 N/C, find the electric flux through the surface.

Solution: The area vector of a surface in the XY-plane points along \[\hat k\]. Since \[\vec E\] has no \[\hat k\] component, \[\vec E\] ⋅ \[\vec A\] = 0.
Flux = 0

CISCE: Class 12

Example 2

Given \[\vec E\] = 5\[\hat i\] + 4\[\hat j\] + 3\[\hat k\] N/C and area vector \[\vec A\] = 100\[\hat k\] m² (surface in XY-plane), find the flux.

Solution: ΦE = \[\vec E\] . \[\vec A\] = (5\[\hat i\] + 4\[\hat j\] + 3\[\hat k\]) ⋅ (100\[\hat k\]) = 300 N m²/C
Flux = 300 units

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