Atomic Spectra

Determine the series limit of Balmer, Paschen and Brackett series, given the limit for Lyman series is 911.6 Å.

Continuous spectrum is produced by ______.

The frequencies for series limit of Balmer and Paschen series respectively are 'v₁' and 'v₃'. If frequency of first line of Balmer series is 'v₂' then the relation between 'v₁', 'v₂' and 'v₃' is ______.

An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. What is the wave number of the emitted radiations? (R = Rydberg's constant)

Deutrium was discovered in 1932 by Harold Urey by measuring the small change in wavelength for a particular transition in ¹H and ²H. This is because, the wavelength of transition depend to a certain extent on the nuclear mass. If nuclear motion is taken into account then the electrons and nucleus revolve around their common centre of mass. Such a system is equivalent to a single particle with a reduced mass µ, revolving around the nucleus at a distance equal to the electron-nucleus separation. Here µ = m_eM/(m_e + M) where M is the nuclear mass and m e is the electronic mass. Estimate the percentage difference in wavelength for the 1st line of the Lyman series in ¹H and ²H. (Mass of ¹H nucleus is 1.6725 × 10^–27 kg, Mass of ²H nucleus is 3.3374 × 10^–27 kg, Mass of electron = 9.109 × 10^–31 kg.)

What is the shortest wavelength present in the Paschen series of spectral lines?

The first four spectral lines in the Lyman series of a H-atom are λ = 1218 Å, 1028Å, 974.3 Å and 951.4 Å. If instead of Hydrogen, we consider Deuterium, calculate the shift in the wavelength of these lines.

Determine the shortest wavelengths of Balmer and Pasch en series. Given the limit for the Lyman series is 912 Å.