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Communication Systems
Introduction
Every time you charge your phone wirelessly, use a transformer, or start a car's ignition, mutual inductance is at work. It is the fundamental principle behind transformers, induction cooktops, RFID cards, and wireless charging pads.
When two coils are placed near each other, a changing current in one coil produces a changing magnetic flux, which links with the neighbouring coil and induces an EMF in it — even without physical contact.
Maharashtra State Board: Class 11
Definition: Mutual Inductance
The property of two coils by which a change in current in one coil induces an emf in the other coil — equal to the magnetic flux linked with one circuit per unit current in the other, or the value of induced emf produced in the secondary circuit per unit rate of change in current in the primary circuit — is called mutual inductance.
OR
Mutual Inductance (M) of a pair of coils is defined as the ratio of the total magnetic flux linkage in the secondary coil to the current in the primary coil that produces it.
Definition: Coefficient of Coupling
The coefficient of coupling K between two coils is the fraction of the total magnetic flux produced by one coil that links with the other coil.
Maharashtra State Board: Class 11
Formula: Mutual Inductance
N2ϕ21 ∝ I1 ⟹ N2ϕ21 = M ⋅ I1
Therefore:
Formula: Coefficient of Coupling
M = K\[\sqrt {L_1L_2}\]
Where:
- L1, L2 = Self-inductances of coil 1 and coil 2
- K = Coefficient of coupling (dimensionless, no units)
- Range: 0 ≤ K ≤ 1
Therefore:
M ≤ \[\sqrt {L_1L_2}\]
EMF Form of Mutual Inductance
From Faraday's Second Law, the EMF induced in the secondary coil is:
\[e_2=-N_2\frac{d\phi_{21}}{dt}=-M\frac{dI_1}{dt}\]
If the rate of change of current in the primary is 1 A/s and the induced EMF in the secondary is 1 V, then M = 1 H (one Henry).
SI Unit and Dimensions
| Property | Value |
|---|---|
| SI Unit | Henry (H) |
| Dimensional Formula | \[\left[ML^{2}T^{-2}A^{-2}\right]\] (same as self-inductance) |
| Other Units | mH (millihenry), μH (microhenry) |
| Named after | Joseph Henry (American scientist) |
1 H = 1 V·s/A = 1 Wb/A
Reciprocity Theorem
Statement: The mutual inductance of coil 1 with respect to coil 2 equals the mutual inductance of coil 2 with respect to coil 1.
This is called the Reciprocity Theorem of Mutual Inductance.
Implication: It does not matter which coil drives the current — the mutual inductance M between the pair is always the same property of the system, not just one coil.youtube
Factors Affecting Mutual Inductance
The value of M between two coils depends on the following:
- Number of turns N1 and N2 — M increases as turns increase (M ∝ N1N2)
- Size and geometry of the coils — larger cross-sectional area → more flux linkage → larger M
- Distance between coils — as distance increases, M decreases (less flux links the secondary)
- Relative orientation — M is maximum when coils are coaxial (same axis); M = 0 when coil axes are perpendicular to each other
- Permeability of the core medium (μr\mu_rμr) — winding coils on a soft iron core greatly increases M
- Coupling factor K — quantifies how efficiently flux is shared between the coils
Derivation: Mutual Inductance of Two Coaxial Solenoids
Setup:
- Solenoid S₁ (primary): length l, N1 turns, n1 = N1/l turns/m, radius r1 (larger)
- Solenoid S₂ (secondary): N2 turns, n2 = N2/l turns/m, radius r2 (smaller, wound inside S₁)
- Current I1 passed through S₁
Step 1: Magnetic field inside S₁:
- B1 = μ0n1I1
Step 2: Flux through each turn of S₂ (area = \[\pi r_2^2\], the smaller radius):
- ϕ21 = B1 ⋅ \[\pi r_2^2\] = μ0n1I1\[\pi r_2^2\]
Step 3: Total flux linkage of S₂:
- N2ϕ21 = μ0n1n2l ⋅ \[\pi r_2^2\] ⋅ I1
Step 4: Mutual Inductance:
- M21 = μ0n1n2\[\pi r_2^2,\]l
Or equivalently (using N1 = n1l and N2 = n2l):
- M = \[\frac{\mu_0N_1N_2A}{l}\]
where A = \[\pi r_2^2\] (cross-sectional area of the inner solenoid).
Similarly: M12 = μ0n1n2\[\pi r_2^2\]l, confirming Reciprocity: M12 = M21 = M.
Special Case — Two Concentric Coplanar Circular Coils
For a small coil of radius r1 placed at the centre of a large coil of radius r2 (where r1 ≪ r2):
M = \[\frac{\mu_0\pi r_1^2}{2r_2}\]
Example
Two concentric circular coils are placed with the same centre and axis. The small coil has radius r1= and the large coil has radius r2, with r1 ≪ r2.
A current I2 is passed through the outer large coil. This creates a magnetic field at its centre:
- B2 = \[\frac{\mu_0I_2}{2r_2}\]
Since the inner coil is very small compared to the outer coil, this field B2 can be assumed uniform across the entire area of the inner coil. This is the key approximation in the problem.
The magnetic flux passing through the inner small coil is then:
- Φ1 = \[\pi r_1^2\cdot B_2=\frac{\mu_0\pi r_1^2I_2}{2r_2}\]
By definition, Φ1 = M12 ⋅ I2. Comparing both sides gives the mutual inductance:
- M = \[\frac{\mu_0\pi r_1^2}{2r_2}\]
Finally, by the Reciprocity Theorem, M12 = M21 = M, so this single value describes the mutual inductance of the entire arrangement regardless of which coil carries the current.
Real-World Applications
| Application | How (M) Is Used |
|---|---|
| Transformer | Steps up or steps down voltage using tightly coupled coils (k ≈ 1). |
| Wireless charging | Loosely coupled coils transfer energy without physical contact. |
| Induction cooktop | Changing the current in the cooktop coil induces current in the cookware. |
Video Tutorials
Shaalaa.com | Electromagnetic Induction part 15 (Inductance)
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