हिंदी
Tamil Nadu Board of Secondary EducationHSC Science Class 11

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity [Latest edition]

Advertisements

Chapters

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity - Shaalaa.com
Advertisements

Solutions for Chapter 9: Differential Calculus - Limits and Continuity

Below listed, you can find solutions for Chapter 9 of Tamil Nadu Board of Secondary Education Samacheer Kalvi for Mathematics - Volume 1 and 2 [English] Class 11 TN Board.


Exercise 9.1Exercise 9.2Exercise 9.3Exercise 9.4Exercise 9.5Exercise 9.6
Exercise 9.1 [Pages 95 - 98]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.1 [Pages 95 - 98]

1Page 95

In problems 1 – 6, using the table estimate the value of the limit.

`lim_(x -> 2) (x - 2)/(x^2 - x - 2)`

x 1.9 1.99 1.999 2.001 2.01 2.1
f(x) 0.344820 0.33444 0.33344 0.333222 0.33222 0.332258
2Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 2) (x - 2)/(x^2 - 4)`

x 1.9 1.99 1.999 2.001 2.01 2.1
f(x) 0.25641 0.25062 0.250062 0.24993 0.24937 0.24390
3Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) (sqrt(x + 3) - sqrt(3))/x`

x – 0.1  – 0.01 – 0.001 0.001 0.01 0.1
f(x) 0.2911 0.2891 0.2886 0.2886 0.2885 0.28631
4Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> - 3) (sqrt(1 - x) - 2)/(x + 3)`

x – 3.1  – 3.01 – 3.00 – 2.999 – 2.99 – 2.9
f(x) – 0.24845 – 0.24984 – 0.24998 – 0.25001 – 0.25015 – 0.25158
5Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) sin x/x`

x – 0.1  – 0.01 – 0.001 0.001 0.01 0.1
f(x) 0.99833 0.99998 0.99999 0.99999 0.99998 0.99833
6Page 95

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) (cos x - 1)/x`

x – 0.1  – 0.01 – 0.001 0.0001 0.01 0.1
f(x) 0.04995 0.0049999 0.0004999 – 0.0004999 – 0.004999 – 0.04995
7Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 3) (4 - x)`

8Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 1) (x^2 + 2)`

9Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 2) f(x)` where `f(x) = {{:(4 - x",", x ≠ 2),(0",", x = 2):}`

10Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 1) f(x)` where `f(x) = {{:(x^2 + 2",", x ≠ 1),(1",", x = 1):}`

11Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 3) 1/(x - 3)`

12Page 96

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 5) |x - 5|/(x - 5)`

13Page 97

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 1) sin pi x`

14Page 97

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 0) sec x`

15Page 97

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> x/2) tan x`

16Page 97

Sketch the graph of f, then identify the values of x0 for which `lim_(x -> x_0)` f(x) exists.

f(x) = `{{:(x^2",", x ≤ 2),(8 - 2x",", 2 < x < 4),(4",", x ≥ 4):}`

17Page 97

Sketch the graph of f, then identify the values of x0 for which `lim_(x -> x_0)` f(x) exists.

f(x) = `{{:(sin x",", x < 0),(1 - cos x",", 0 ≤ x ≤ pi),(cos x",", x > pi):}`

18. (i)Page 97

Sketch the graph of a function f that satisfies the given value:

f(0) is undefined

`lim_(x -> 0) f(x)` = 4

f(2) = 6

`lim_(x -> 2) f(x)` = 3

18. (ii)Page 97

Sketch the graph of a function f that satisfies the given value:

f(– 2) = 0

f(2) = 0

`lim_(x -> 2) f(x)` = 0

`lim_(x -> 2) f(x)` does not exist.

19Page 98

Write a brief description of the meaning of the notation `lim_(x -> 8) f(x)` = 25

20Page 98

If f(2) = 4, can you conclude anything about the limit of f(x) as x approaches 2?

21Page 98

If the limit of f(x) as x approaches 2 is 4, can you conclude anything about f(2)? Explain reasoning

22Page 98

Evaluate : `lim_(x -> 3) (x^2 - 9)/(x - 3)` if it exists by finding `f(3^-)` and `f(3^+)`

23Page 98

Verify the existence of `lim_(x -> 1) f(x)`, where `f(x) = {{:((|x - 1|)/(x - 1)",",  "for"  x ≠ 1),(0",",  "for"  x = 1):}`

Exercise 9.2 [Pages 102 - 103]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.2 [Pages 102 - 103]

1Page 102

Evaluate the following limits:

`lim_(x -> 2) (x^4 - 16)/(x - 2)`

2Page 102

Evaluate the following limits:

`lim_(x ->) (x^"m" - 1)/(x^"n" - 1)`, m and n are integers

3Page 102

Evaluate the following limits:

`lim_(sqrt(x) -> 3) (x^2 - 81)/(sqrt(x) - 3)`

4Page 102

Evaluate the following limits:

`lim_("h" -> 0) (sqrt(x + "h") - sqrt(x))/"h", x > 0`

5Page 102

Evaluate the following limits:

`lim_(x -> 5) (sqrt(x + 4) - 3)/(x - 5)`

6Page 103

Evaluate the following limits:

`lim_(x -> 2) (1/x - 1/2)/(x - 2)`

7Page 103

Evaluate the following limits:

`lim_(x -> 1) (sqrt(x) - x^2)/(1 - sqrt(x))`

8Page 103

Evaluate the following limits:

`lim_(x -> 0) (sqrt(x^2 + 1) - 1)/(sqrt(x^2 + 16) - 4)`

9Page 103

Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 + x) - 1)/x`

10Page 103

Evaluate the following limits:

`lim_(x -> 1) (root(3)(7 + x^3) - sqrt(3 + x^2))/(x - 1)`

11Page 103

Evaluate the following limits:

`lim_(x -> 2) (2 - sqrt(x + 2))/(root(3)(2) - root(3)(4 - x))`

12Page 103

Evaluate the following limits:

`lim_(x - 0) (sqrt(1 + x^2) - 1)/x`

13Page 103

Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 - x) - 1)/x^2`

14Page 103

Evaluate the following limits:

`lim_(x -> 5) (sqrt(x - 1) - 2)/(x - 5)`

15Page 103

Evaluate the following limits:

`lim_(x -> "a") (sqrt(x - "b") - sqrt("a" - "b"))/(x^2 - "a"^2) ("a" > "b")`

Exercise 9.3 [Page 111]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.3 [Page 111]

1. (a)Page 111

Find the left and right limits of f(x) = `(x^2 - 4)/((x^2 + 4x+ 4)(x + 3))` at x = – 2

1. (b)Page 111

Find the left and right limits of f(x) = tan x at x = `pi/2`

2Page 111

Evaluate the following limits:

`lim_(x -> 3) (x^2 - 9)/(x^2(x^2 - 6x + 9))`

3Page 111

Evaluate the following limits:

`lim_(x  -> oo) 3/(x - 2) - (2x + 11)/(x^2 + x - 6)`

4Page 111

Evaluate the following limits:

`lim_(x -> oo) (x^3 + x)/(x^4 - 3x^2 + 1)`

5Page 111

Evaluate the following limits:

`lim_(x -> oo) (x^4 - 5x)/(x^2 - 3x + 1)`

6Page 111

Evaluate the following limits:

`lim_(x -> oo) (1 + x - 3x^3)/(1 + x^2 +3x^3)`

7Page 111

Evaluate the following limits:

`lim_(x ->oo) (x^3/(2x^2 - 1) - x^2/(2x + 1))`

8. (i)Page 111

Show that `lim_("n" -> oo) (1 + 2 + 3 + ... + "n")/(3"n"^2 + 7n" + 2) = 1/6`

8. (ii)Page 111

Show that  `lim_("n" -> oo) (1^2 + 2^2 + ... + (3"n")^2)/((1 + 2 + ... + 5"n")(2"n" + 3)) = 9/25`

8. (iii)Page 111

Show that `lim_("n" -> oo) 1/1.2 + 1/2.3 + 1/3.4 + ... + 1/("n"("n" + 1))` = 1

9Page 111

An important problem in fishery science is to estimate the number of fish presently spawning in streams and use this information to predict the number of mature fish or “recruits” that will return to the rivers during the reproductive period. If S is the number of spawners and R the number of recruits, “Beverton-Holt spawner recruit function” is R(S) = `"S"/((alpha"S" + beta)` where `alpha` and `beta` are positive constants. Show that this function predicts approximately constant recruitment when the number of spawners is sufficiently large

10Page 111

A tank contains 5000 litres of pure water. Brine (very salty water) that contains 30 grams of salt per litre of water is pumped into the tank at a rate of 25 litres per minute. The concentration of salt water after t minutes (in grams per litre) is C(t) = `(30"t")/(200 + "t")`. What happens to the concentration as t → ∞?

Exercise 9.4 [Pages 117 - 118]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.4 [Pages 117 - 118]

1Page 117

Evaluate the following limits:

`lim_(x -> oo)(1 + 1/x)^(7x)`

2Page 117

Evaluate the following limits:

`lim_(x -> 0)(1 + x)^(1/(3x))`

3Page 117

Evaluate the following limits:

`lim_(x -> oo)(1 + "k"/x)^("m"/x)`

4Page 117

Evaluate the following limits:

`lim_(x -> oo) ((2x^2 + 3)/(2x^2 + 5))^(8x^2 + 3)`

5Page 118

Evaluate the following limits:

`lim_(x -> oo) (1 + 3/x)^(x + 2)`

6Page 118

Evaluate the following limits:

`lim_(x -> 0) (sin^3(x/2))/x^2`

7Page 118

Evaluate the following limits:

`lim_(x -> 0) (sinalphax)/(sinbetax)`

8Page 118

Evaluate the following limits:

`lim_(x -> 0) (tan 2x)/(sin 5x)`

9Page 118

Evaluate the following limits:

`lim_(alpha -> 0) (sin(alpha^"n"))/(sin alpha)^"m"`

10Page 118

Evaluate the following limits:

`lim_(x -> 0) (sin("a" + x) - sin("a" - x))/x`

11Page 118

Evaluate the following limits:

`lim_(x -> 0) (sqrt(x^2 + "a"^2) - "a")/(sqrt(x^2 + "b"^2) - "b")`

12Page 118

Evaluate the following limits:

`lim_(x -> 0) (2 "arc"sinx)/(3x)`

13Page 118

Evaluate the following limits:

`lim_(x-> 0) (1 - cos x)/x^2`

14Page 118

Evaluate the following limits:

`lim_(x -> 0) (tan 2x)/x`

15Page 118

Evaluate the following limits:

`lim_(x -> 0) (2^x - 3^x)/x`

16Page 118

Evaluate the following limits:

`lim_(x -> 0) (3^x - 1)/(sqrt(x + 1) - 1)`

17Page 118

Evaluate the following limits:

`lim_(x -> 0) (1 - cos^2x)/(x sin2x)`

18Page 118

Evaluate the following limits:

`lim_(x -> oo) x [3^(1/x) + 1 - cos(1/x) - "e"^(1/x)]`

19Page 118

Evaluate the following limits:

`lim_(x - oo){x[log(x + "a") - log(x)]}`

20Page 118

Evaluate the following limits:

`lim_(x -> pi) (sin3x)/(sin2x)`

21Page 118

Evaluate the following limits:

`lim_(x -> pi) (1 + sinx)^(2"cosec"x)`

22Page 118

Evaluate the following limits:

`lim_(x -> 0) (sqrt(2) - sqrt(1 + cosx))/(sin^2x)`

23Page 118

Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 + sinx) - sqrt(1 - sinx))/tanx`

24Page 118

Evaluate the following limits:

`lim_(x -> oo) ((x^2 - 2x + 1)/(x^2 -4x + 2))^x`

25Page 118

Evaluate the following limits:

`lim_(x -> 0) ("e"^x - "e"^(-x))/sinx`

26Page 118

Evaluate the following limits:

`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x`

27Page 118

Evaluate the following limits:

`lim_(x -> ) (sinx(1 - cosx))/x^3`

28Page 118

Evaluate the following limits:

`lim_(x -> 0) (tan x - sin x)/x^3`

Exercise 9.5 [Pages 127 - 129]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.5 [Pages 127 - 129]

1Page 127

Prove that f(x) = 2x2 + 3x - 5 is continuous at all points in R

2. (i)Page 127

Examine the continuity of the following:

x + sin x

2. (ii)Page 127

Examine the continuity of the following:

x2 cos x

2. (iii)Page 127

Examine the continuity of the following:

ex tan x

2. (iv)Page 127

Examine the continuity of the following:

e2x + x2

2. (v)Page 127

Examine the continuity of the following:

x . log x

2. (vi)Page 127

Examine the continuity of the following:

`sinx/x^2`

2. (vii)Page 127

Examine the continuity of the following:

`(x^2 - 16)/(x + 4)`

2. (viii)Page 127

Examine the continuity of the following:

|x + 2| + |x – 1|

2. (ix)Page 127

Examine the continuity of the following:

`|x - 2|/|x + 1|`

2. (x)Page 127

Examine the continuity of the following:

cot x + tan x

3. (i)Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(4x + 5",",  "if",  x ≤ 3),(4x - 5",",  "if",  x > 3):}`

3. (ii)Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(x + 2",",  "if",  x ≥ 2),(x^2",",  "if",  x < 2):}`

3. (iii)Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(x^3 - 3",",  "if"  x ≤ 2),(x^2 + 1",",  "if"  x < 2):}`

3. (iv)Page 127

Find the points of discontinuity of the function f, where `f(x) = {{:(sinx",",  0 ≤ x ≤ pi/4),(cos x",", pi/4 < x < pi/2):}`

4. (i)Page 127

At the given point x0 discover whether the given function is continuous or discontinuous citing the reasons for your answer:

x0 = 1, `f(x) = {{:((x^2 - 1)/(x - 1)",", x ≠ 1),(2",", x = 1):}`

4. (ii)Page 127

At the given point x0 discover whether the given function is continuous or discontinuous citing the reasons for your answer:

x0 = 3, `f(x) = {{:((x^2 - 9)/(x - 3)",", "if"  x ≠ 3),(5",", "if"  x = 3):}`

5Page 127

Show that the function `{{:((x^3 - 1)/(x - 1)",",  "if"  x ≠ 1),(3",",  "if"  x = 1):}` is continuous om `(- oo, oo)`

6Page 127

For what value of `alpha` is this function `f(x) = {{:((x^4 - 1)/(x - 1)",",  "if"  x ≠ 1),(alpha",",  "if"  x = 1):}` continuous at x = 1?

7Page 128

Let `f(x) = {{:(0",",  "if"  x < 0),(x^2",",  "if"  0 ≤ x ≤ 2),(4",",  "if"  x ≥ 2):}`. Graph the function. Show that f(x) continuous on `(- oo, oo)`

8Page 128

If f and g are continuous functions with f(3) = 5 and `lim_(x -> 3) [2f(x) - g(x)]` = 4, find g(3)

9. (i)Page 128

Find the points at which f is discontinuous. At which of these points f is continuous from the right, from the left, or neither? Sketch the graph of f.

`f(x) = {{:(2x + 1",",  "if"  x ≤ - 1),(3x",",  "if"  - 1 < x < 1),(2x - 1",",  "if"  x ≥ 1):}`

9. (ii)Page 128

Find the points at which f is discontinuous. At which of these points f is continuous from the right, from the left, or neither? Sketch the graph of f.

`f(x) = {{:((x - 1)^3",",  "if"  x < 0),((x + 1)^3",",  "if"  x ≥ 0):}`

10Page 128

A function f is defined as follows:

`f(x) = {{:(0,  "for"  x < 0;),(x,  "for"  0 ≤ x ≤ 1;),(- x^2 +4x - 2, "for"  1 ≤ x ≤ 3;),(4 - x,  "for"  x ≥ 3):}`
Is the function continuous?

11. (i)Page 128

Which of the following functions f has a removable discontinuity at x = x0? If the discontinuity is removable, find a function g that agrees with f for x ≠ x0 and is continuous on R.

`f(x) = (x^2 - 2x - 8)/(x + 2), x_0` = – 2

11. (ii)Page 128

Which of the following functions f has a removable discontinuity at x = x0? If the discontinuity is removable, find a function g that agrees with f for x ≠ x0 and is continuous on R.

`f(x) = (x^3 + 64)/(x + 4), x_0` = – 4

11. (iii)Page 128

Which of the following functions f has a removable discontinuity at x = x0? If the discontinuity is removable, find a function g that agrees with f for x ≠ x0 and is continuous on R.

`f(x) = (3 - sqrt(x))/(9 - x), x_0` = 9

12Page 128

Find the constant b that makes g continuous on `(- oo, oo)`.

`g(x) = {{:(x^2 - "b"^2,"if"  x < 4),("b"x + 20,  "if"  x ≥ 4):}`

13Page 128

Consider the function  `f(x) = x sin  pi/x`. What value must we give f(0) in order to make the function continuous everywhere?

14Page 128

The function `f(x) = (x^2 - 1)/(x^3 - 1)` is not defined at x = 1. What value must we give f(1) inorder to make f(x) continuous at x =1?

15. (a)Page 129

State how continuity is destroyed at x = x0 for the following graphs.

15. (b)Page 129

State how continuity is destroyed at x = x0 for the following graphs.

15. (c)Page 129

State how continuity is destroyed at x = x0 for the following graphs.

15. (d)Page 129

State how continuity is destroyed at x = x0 for the following graphs.

Exercise 9.6 [Pages 129 - 131]

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board 9 Differential Calculus - Limits and Continuity Exercise 9.6 [Pages 129 - 131]

1Page 129

Choose the correct alternative:

`lim_(x -> oo) sinx/x`

  • 1

  • 0

  • `oo`

  • `- oo`

2Page 129

Choose the correct alternative:

`lim_(x - pi/2) (2x - pi)/cos x`

  • 2

  • 1

  • −2

  • 0

3Page 129

Choose the correct alternative:

`lim_(x -> 0) sqrt(1 - cos 2x)/x`

  • 0

  • 1

  • `sqrt(2)`

  • does not exist

4Page 129

Choose the correct alternative:

`lim_(theta -> 0) (sinsqrt(theta))/(sqrt(sin theta)`

  • 1

  • – 1

  • 0

  • 2

5Page 129

Choose the correct alternative:

`lim_(x -> oo) ((x^2 + 5x + 3)/(x^2 + x + 3))^x` is

  • e4

  • e2

  • e3

  • 1

6Page 130

Choose the correct alternative:

`lim_(x - oo) sqrt(x^2 - 1)/(2x + 1)` =

  • 1

  • 0

  • – 1

  • `1/2`

7Page 130

Choose the correct alternative:

`lim_(x -> 0) ("a"^x - "b"^x)/x` =

  • log ab

  • `log ("a"/"b")`

  • `log ("b"/"a")`

  • `"a"/"b"`

8Page 130

Choose the correct alternative:

`lim_(x -> 0) (8^x - 4x - 2^x + 1^x)/x^2` =

  • 2 log 2

  • 2(log)2 

  • log 2

  • 3 log 2

9Page 130

Choose the correct alternative:

If `f(x) = x(- 1)^([1/x])`, x ≤ 0, then the value of `lim_(x -> 0) f(x)` is equal to

  • – 1

  • 0

  • 2

  • 4

10Page 130

Choose the correct alternative:

`lim_(x -> 3) [x]` =

  • 2

  • 3

  • does not exist

  • 0

11Page 130

Choose the correct alternative:

Let the function f be defined by `f(x) = {{:(3x, 0 ≤ x ≤ 1),(-3 + 5, 1 < x ≤ 2):}`, then

  • `lim_(x -> 1) f(x)` = 1

  • `lim_(x -> 1) f(x)` = 3

  • `lim_(x -> 1) f(x)` = 2

  • `lim_(x -> 1) f(x)` does not exist

12Page 130

Choose the correct alternative:

If f : R → R is defined by `f(x) = [x - 3] + |x - 4|` for x ∈ R then `lim_(x -> 3^-) f(x)` is equal to

  • – 2

  • – 1

  • 0

  • 1

13Page 130

Choose the correct alternative:

`lim_(x -> 0) (x"e"^x - sin x)/x` is

  • 1

  • 2

  • 3

  • 0

14Page 130

Choose the correct alternative:

If `lim_(x -> 0) (sin "p"x)/(tan 3x)` = 4, then the value of p is

  • 6

  • 9

  • 12

  • 4

15Page 130

Choose the correct alternative:

`lim_(alpha - pi/4) (sin alpha - cos alpha)/(alpha - pi/4)` is

  • `sqrt(2)`

  • `1/sqrt(2)`

  • 1

  • 2

16Page 130

Choose the correct alternative:

`lim_(x -> oo) (1/"n"^2 + 2/"n"^2 + 3/"n"^2 + ... + "n"/"n"^2)` is

  • `1/2`

  • 0

  • 1

  • `oo`

17Page 131

Choose the correct alternative:

`lim_(x -> 0) ("e"^(sin x) - 1)/x` =

  • 1

  • e

  • `1/"e"`

  • 0

18Page 131

Choose the correct alternative:

`lim_(x -> 0) ("e"^tanx - "e"^x)/(tan x - x)` =

  • 1

  • e

  • `1/2`

  • 0

19Page 131

Choose the correct alternative:

The value of `lim_(x -> 0) sinx/sqrt(x^2)` is

  • 1

  • – 1

  • 0

  • limit does not exist

20Page 131

Choose the correct alternative:

The value of `lim_(x -> "k") x - [x]`, where k is an integer is

  • – 1

  • 1

  • 0

  • 2

21Page 131

Choose the correct alternative:

At x = `3/2` the function f(x) = `|2x - 3|/(2x - 3)` is

  • Continuous

  • Discontinuous

  • Differentiable

  • Non-zero

22Page 131

Choose the correct alternative:

Let f : R → R be defined by `f(x) = {{:(x, x  "is irrational"),(1 - x, x  "is rational"):}` then f is

  • Discontinuous at x = `1/2`

  • Continuous at x = `1/2`

  • Continuous everywhere

  • Discontinuous everywhere

23Page 131

Choose the correct alternative:

The function `f(x) = {{:((x^2 - 1)/(x^3 + 1), x ≠ - 1),("P", x = -1):}` is not defined for x = −1. The value of f(−1) so that the function extended by this value is continuous is

  • `2/3`

  • `- 2/3`

  • 1

  • 0

24Page 131

Choose the correct alternative:

Let f be a continuous function on [2, 5]. If f takes only rational values for all x and f(3) = 12, then f(4.5) is equal to

  • `(f(3) + f(4.5))/7.5`

  • 12

  • 17.5

  • `(f(4.5) - f(3))/1.5`

25Page 131

Choose the correct alternative:

Let a function f be defined by `f(x) = (x - |x|)/x` for x ≠ 0 and f(0) = 2. Then f is

  • Continuous nowhere

  • Continuous everywhere

  • Continuous for all x except x = 1

  • Continuous for all x except x = 0

Solutions for 9: Differential Calculus - Limits and Continuity

Exercise 9.1Exercise 9.2Exercise 9.3Exercise 9.4Exercise 9.5Exercise 9.6
Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity - Shaalaa.com

Samacheer Kalvi solutions for Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 - Differential Calculus - Limits and Continuity

Shaalaa.com has the Tamil Nadu Board of Secondary Education Mathematics Mathematics - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Samacheer Kalvi solutions for Mathematics Mathematics - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education 9 (Differential Calculus - Limits and Continuity) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Samacheer Kalvi textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics - Volume 1 and 2 [English] Class 11 TN Board chapter 9 Differential Calculus - Limits and Continuity are Concept of Limits, Differential Calculus, Continuous and Discontinuous Functions.

Using Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board solutions Differential Calculus - Limits and Continuity exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Samacheer Kalvi Solutions are essential questions that can be asked in the final exam. Maximum Tamil Nadu Board of Secondary Education Mathematics - Volume 1 and 2 [English] Class 11 TN Board students prefer Samacheer Kalvi Textbook Solutions to score more in exams.

Get the free view of Chapter 9, Differential Calculus - Limits and Continuity Mathematics - Volume 1 and 2 [English] Class 11 TN Board additional questions for Mathematics Mathematics - Volume 1 and 2 [English] Class 11 TN Board Tamil Nadu Board of Secondary Education, and you can use Shaalaa.com to keep it handy for your exam preparation.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×