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In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why? limx→0secx - Mathematics

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प्रश्न

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 0) sec x`

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उत्तर

To find `lim_(x -> 0) sec x`

Let y = f(x) = sec x

From the graph at x = 0 the curve intersect the y – axis.

At x = 0 we have y = 1

∴ `lim_(x -> 0) sec x` = 1

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.1 [पृष्ठ ९७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.1 | Q 14 | पृष्ठ ९७

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