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Evaluate the following limits: limx→02x-3xx

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प्रश्न

Evaluate the following limits:

`lim_(x -> 0) (2^x - 3^x)/x`

योग
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उत्तर

We know  `lim_(x -> 0) ("a"^x - 1)/x = log "a", "a" > 0`

`lim_(x -> 0) (2^x - 3^x)/x =  lim_(x -> 0) (2^x - 1 + 1 - 3^x)/x`

= `lim_(x -> 0) ((2^x - 1) - (3^x - 1))/x`

= `lim_(x -> 0) ((2^x - 1)/x - (3^x - 1)/x)`

= `lim_(x -> 0) ((2^x - 1)/x) - lim_(x -> 0) ((3^x - 1)/x)`

= log 2 – log 3

`lim_(x -> 0) (2^x - 3^x)/x = log  2/3`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 15 | पृष्ठ ११८

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