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Tamil Nadu Board of Secondary EducationHSC Science Class 11

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why? limx→0secx

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Question

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 0) sec x`

Graph
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Solution

To find `lim_(x -> 0) sec x`

Let y = f(x) = sec x

From the graph at x = 0 the curve intersect the y – axis.

At x = 0 we have y = 1

∴ `lim_(x -> 0) sec x` = 1

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Chapter 9: Differential Calculus - Limits and Continuity - Exercise 9.1 [Page 97]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 9 Differential Calculus - Limits and Continuity
Exercise 9.1 | Q 14 | Page 97

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