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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Evaluate the following limits: eaeblimx→0eax-ebxx

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प्रश्न

Evaluate the following limits:

`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x`

योग
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उत्तर

We know `lim_(x -> 0) ("e"^x - 1)/x` = 1

`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x =  lim_(x -> 0) ("e"^("a"x) - 1 + 1 - "e"^("b"x))/x`

= `lim_(x -> 0) [(("e"^("a"x) - 1)/x) - (("e"^("b"x) - 1)/x)]`

= `lim_(x ->0) (("e"^("a"x) - 1)/(1/"a" ("a"x)))- lim_(x ->0) (("e"^("b"x) - 1)/(1/"b" ("b"x)))`

= `"a" lim_("a"x -> 0) (("e"^("a"x) - 1)/("a"x)) - "b" lim_("b"x -> 0) (("e"^("b"x) - 1)/("b"x))`

= a × 1 – b × 1

= a – b

`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x` = a – b

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 26 | पृष्ठ ११८

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