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प्रश्न
Evaluate the following limits:
`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x`
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उत्तर
We know `lim_(x -> 0) ("e"^x - 1)/x` = 1
`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x = lim_(x -> 0) ("e"^("a"x) - 1 + 1 - "e"^("b"x))/x`
= `lim_(x -> 0) [(("e"^("a"x) - 1)/x) - (("e"^("b"x) - 1)/x)]`
= `lim_(x ->0) (("e"^("a"x) - 1)/(1/"a" ("a"x)))- lim_(x ->0) (("e"^("b"x) - 1)/(1/"b" ("b"x)))`
= `"a" lim_("a"x -> 0) (("e"^("a"x) - 1)/("a"x)) - "b" lim_("b"x -> 0) (("e"^("b"x) - 1)/("b"x))`
= a × 1 – b × 1
= a – b
`lim_(x -> 0) ("e"^("a"x) - "e"^("b"x))/x` = a – b
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