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Evaluate the following limits: limx→01-cosxx2

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प्रश्न

Evaluate the following limits:

`lim_(x-> 0) (1 - cos x)/x^2`

योग
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उत्तर

We know `lim_(x -> 0) (sin x)/x` = 1

`lim_(x -> 0) (1 - cosx)/x^2 =  lim_(x -> 0) (2sin^2(x/2))/x^2`

= `lim_(x -> 0) (2sin^2(x/2))/(2^2 xx x^2/2^2`

= `1/2 lim_(x/2 -> 0) (sin^2 (x/2))/(x/2)^2`

`1/2 [lim_(x/2 -> 0) (sin(x/2))/((x/2))]^2`

`lim_(x -> 0) (1 - cosx)/x^2 = 1/2 xx 1^2`

= `1/2`

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अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 13 | पृष्ठ ११८

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