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Evaluate the following limits: limx→0sinαxsinβx - Mathematics

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प्रश्न

Evaluate the following limits:

`lim_(x -> 0) (sinalphax)/(sinbetax)`

योग
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उत्तर

We know `lim_(x -> 0) sinx/x` = 1

`lim_(x -> 0) (sin alpha x)/(sin betax) =  lim_(x -> 0) (sin alphax)/(1/alpha (alphax)) xx (1/beta (betax))/(sin betax)`

= `alpha/beta lim_(x -> 0) (sin(alphax))/((alphax)) xx (betax)/(sin(betax))` 

= `alpha/beta lim_(alphax -> 0) (sin(alphax))/(alphax) xx lim_(betax -> 0) (betax)/(sin(betax))`

= `alpha/beta lim_(alphax -> 0) (sin(alphax))/(alphax) xx 1/(lim_(betax -> 0) (sin("betax))/(betax))`

= `alpha/beta xx 1 xx 1/1`

`lim_(x -> 0) (sinalphax)/(sinbetax) = alpha/beta`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 7 | पृष्ठ ११८

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