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Evaluate the following limits: limx→0sin3(x2)x2

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प्रश्न

Evaluate the following limits:

`lim_(x -> 0) (sin^3(x/2))/x^2`

योग
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उत्तर

We know `lim_(x -> 0) sinx/x` = 1

`lim_(x -> 0) (sin^3(x/2))/x^3 =  lim_(x -> 0) (sin^3(x/2))/(2^3 xx x^3/2^3)`

= `lim_(x/2 -> 0) 1/8* (sin^3(x/2))/(x/2)^3`

= `1/8 lim_(x/2 -> 0) [(sin (x/2))/(x/2)]^3`

`lim_(x -> 0) (sin^3(x/2))/x^2 = 1/8 xx 1^3`

= `1/8`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 6 | पृष्ठ ११८

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