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Evaluate the following limits: limx→sinx(1-cosx)x3

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प्रश्न

Evaluate the following limits:

`lim_(x -> ) (sinx(1 - cosx))/x^3`

योग
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उत्तर

We know `lim_(x -> 0) sinx/x` = 1

`lim_(x -> 0) (sinx(1 - cosx))/x^3 =  lim_(x -> 0) (sinx xx 2 sin^2  x/2)/x^3`

= `lim_(x -> 0) (sinx/x) xx 2 (sin^2  x/2)/x^2`

= `lim_(x -> 0) (sinx/x) xx 2 (sin^2  x/2)/(2^2 xx x^2/2^2)`

= `lim_(x -> 0) [(sinx/x) xx 1/2 ((sin (x/2))/((x/2)))^2]`

= `lim_(x -> 0) (sinx/x) xx 1/2 (lim_(x/2 -> 0)  (sin  x/2)/(x/2))^2`

= `1 xx 1/2 xx 1`

`lim_(x -> ) (sinx(1 - cosx))/x^3 = 1/2`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 27 | पृष्ठ ११८

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