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Evaluate the following limits: limx→0x2+1-1x2+16-4

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प्रश्न

Evaluate the following limits:

`lim_(x -> 0) (sqrt(x^2 + 1) - 1)/(sqrt(x^2 + 16) - 4)`

योग
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उत्तर

`lim_(x -> 0) [(sqrt(x^2 + 1) - 1)/(sqrt(x^2 + 16) - 4)] =  lim_(x -> 0) [(sqrt(x^2 + 1) - 1) xx ((sqrt(x^2 + 1) + 1))/((sqrt(x^2 + 1) + 1)) xx 1/sqrt(x^2 + 16 - 4) xx (sqrt(x^2 + 16) + 4)/(sqrt(x^2 + 16) + 4)]`

= `lim_(x -> 0) [(x^2 + 1 - 1)/(sqrt(x^2 + 1) + 1) xx (sqrt(x^2 + 16) + 4)/(x^2 + 16 - 16)]`

= `lim_(x -> 0) [x^2/(sqrt(x^2 + 1) + 1) xx (sqrt(x^2 + 16) + 4)/x^2]`

= `lim_(x -> 0) [(sqrt(x^2 + 16) + 4)/(sqrt(x^2 + 1) + 1)]`

= `(sqrt(0^2 + 16) + 4)/(sqrt(0^2 + 1) + 1)`

= `(4 + 4)/(1 + 1)`

`lim_(x -> 0) (sqrt(x^2 + 1) - 1)/(sqrt(x^2 + 16) - 4) = 8/2` = 4

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.2 [पृष्ठ १०३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.2 | Q 8 | पृष्ठ १०३

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