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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Evaluate the following limits: limx→02-1+cosxsin2x

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प्रश्न

Evaluate the following limits:

`lim_(x -> 0) (sqrt(2) - sqrt(1 + cosx))/(sin^2x)`

योग
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उत्तर

`lim_(x -> 0) ((sqrt(2) - sqrt(1 + cosx))/(sin^2x))`

= `lim_(x -> 0) ((sqrt(2) - sqrt(1 + cosx))(sqrt(2) + sqrt(1 +  cosx)))/(sin^2x (sqrt(2) + sqrt(1 + cosx))`

= `lim_(x -> 0) (2 - (1 + cosx))/((1 - cos^2x)(sqrt(2) + sqrt(1 + cosx))`

= `lim_(x -> 0) (1 - cosx)/((1 +cosx)(1 - cosx)(sqrt(2) + sqrt(1 + cosx))`

= `lim_(x -> 0) 1/((1 + cosx)(sqrt(2) + sqrt(1 + cosx))`

= `1/((1 + cos0)(sqrt(2) + sqrt(1 + 1))`

= `1/(2(sqrt(2) + sqrt(2))`

=`1/(2 xx 2sqrt(2))`

`lim_(x -> 0) (sqrt(2) - sqrt(1 + cosx))/(sin^2x) = 1/(4sqrt(2))`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 22 | पृष्ठ ११८

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