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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Evaluate the following limits: limx→0tan2xsin5x

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प्रश्न

Evaluate the following limits:

`lim_(x -> 0) (tan 2x)/(sin 5x)`

योग
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उत्तर

We know  `lim_(x -> 0) (sin x)/x` = 1

`lim_(x -> 0) (tan 2x)/(sin 5x) =  lim_(x -> 0) (sin 2x)/(cos  2x) xx 1/(sin 5x)`

= `lim_(x -> 0) (sin 2x)/(1/2 (2x)) xx 1/(cos 2x) xx (1/5(5x))/(sin 5x)`

= `2/5 (lim_(2x-> 0) (sin 2x)/(2x)) (lim_(x -> 0) 1/(cos 2x)) xx (1/(lim_(5x -> 0) (sin 5x)/(5x)))`

= `2/5 xx 1 xx 1/cos  0 xx 1/1`

`lim_(x -> 0) (tan 2x)/(sin 5x) = 2/5 xx 1/1 xx 1` 

= `2/5`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 8 | पृष्ठ ११८

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