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A tank contains 5000 litres of pure water. Brine (very salty water) that contains 30 grams of salt per litre of water is pumped into the tank at a rate of 25 litres per minute. The concentration

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प्रश्न

A tank contains 5000 litres of pure water. Brine (very salty water) that contains 30 grams of salt per litre of water is pumped into the tank at a rate of 25 litres per minute. The concentration of salt water after t minutes (in grams per litre) is C(t) = `(30"t")/(200 + "t")`. What happens to the concentration as t → ∞?

योग
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उत्तर

Given the concentration of saltwater after t minutes is C(t) = `(30"t")/(200 + "t")`

 To find the concentration of saltwater after t → ∞

`lim_("t" -> oo) "C"("t") =  lim_("t" -> oo) (30"t")/(200 + "t")`

= `lim_("t" -> oo) (30"t")/("t"(200/"t" + 1))`

= `lim_("t" -> oo) (30"t")/(200/"t" + 1)`

= `30/(0 + 1)`

`lim_("t" -> oo) "C"("t")` = 30

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.3 [पृष्ठ १११]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.3 | Q 10 | पृष्ठ १११

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