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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

In problems 1 – 6, using the table estimate the value of the limit. limx→2x-2x2-x-2 x 1.9 1.99 1.999 2.001 2.01 2.1 f(x) 0.344820 0.33444 0.33344 0.333222 0.33222 0.332258

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प्रश्न

In problems 1 – 6, using the table estimate the value of the limit.

`lim_(x -> 2) (x - 2)/(x^2 - x - 2)`

x 1.9 1.99 1.999 2.001 2.01 2.1
f(x) 0.344820 0.33444 0.33344 0.333222 0.33222 0.332258
सारिणी
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उत्तर

`lim_(x -> 2) (x - 2)/(x^2 - x - 2) =  lim_(x -> 2) ( x - 2)/((x - 2)(x + 1))`

= `lim_(x -> 2) (x - 2)/(x + 1)`

1.9 1.99 1.999 2.001 20.1 2.1
f(x)

`1/(1.9 + 1)`

= `1/2.9`

= 0.34

`1/(1.99 + 1)`

= `1/2.99`

= 0.33

`1/(1.999 + 1)`

= `1/2.99`

= 0.33

`1/(2.001 + 1)`

= `1/3.001`

= 0.33

`1/(2.01 + 1)`

= `1/3.01`

= 0.33

`1/(2.1 + 1)`

= `1/3.1`

= 0.32

`lim_(x -> 2) (x - 2)/(x^2 - x - 2)` = 0.3

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.1 [पृष्ठ ९५]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.1 | Q 1 | पृष्ठ ९५

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