हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Evaluate the following limits: kmlimx→∞(1+kx)mx

Advertisements
Advertisements

प्रश्न

Evaluate the following limits:

`lim_(x -> oo)(1 + "k"/x)^("m"/x)`

योग
Advertisements

उत्तर

Let A = `lim_(x -> oo)(1 + "k"/x)^("m"/x)`

Put `"k"/x` = y

`"m"/x = "m"/"k" * y`

When x → ∞

We have y → 0

∴ A = `lim_(y -> 0) (1 + y)^("m"/"k" * y)`

log A = `log[lim_(y -> 0) (1 + y)^("m"/"k" * y)]`

= `lim_(y -> 0)[log(1 +y)^("m"/"k" * y)]`

= `lim_(y -> 0) ["m"/"k" * y log(1 + y)]`

= `"m"/"k" xx 0 xx log(1 + 0)`

log A = `"m/"k" xx 0 xx 0` = 0

A = e0

`lim_(x -> oo)(1 + "k"/x)^("m"/x)` = 1

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [पृष्ठ ११७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 3 | पृष्ठ ११७

संबंधित प्रश्न

Evaluate the following limit :

`lim_(z -> "a")[((z + 2)^(3/2) - ("a" + 2)^(3/2))/(z - "a")]`


Evaluate the following :

Given that 7x ≤ f(x) ≤ 3x2 – 6 for all x. Determine the value of `lim_(x -> 3) "f"(x)`


In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) sin x/x`

x – 0.1  – 0.01 – 0.001 0.001 0.01 0.1
f(x) 0.99833 0.99998 0.99999 0.99999 0.99998 0.99833

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 5) |x - 5|/(x - 5)`


Sketch the graph of a function f that satisfies the given value:

f(0) is undefined

`lim_(x -> 0) f(x)` = 4

f(2) = 6

`lim_(x -> 2) f(x)` = 3


Write a brief description of the meaning of the notation `lim_(x -> 8) f(x)` = 25


Evaluate the following limits:

`lim_(x -> 1) (root(3)(7 + x^3) - sqrt(3 + x^2))/(x - 1)`


Evaluate the following limits:

`lim_(x -> 2) (2 - sqrt(x + 2))/(root(3)(2) - root(3)(4 - x))`


Evaluate the following limits:

`lim_(x - 0) (sqrt(1 + x^2) - 1)/x`


Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 - x) - 1)/x^2`


Evaluate the following limits:

`lim_(x -> oo) (x^4 - 5x)/(x^2 - 3x + 1)`


Evaluate the following limits:

`lim_(x -> oo) ((2x^2 + 3)/(2x^2 + 5))^(8x^2 + 3)`


Evaluate the following limits:

`lim_(x -> 0) (2 "arc"sinx)/(3x)`


Evaluate the following limits:

`lim_(x-> 0) (1 - cos x)/x^2`


Evaluate the following limits:

`lim_(x -> pi) (1 + sinx)^(2"cosec"x)`


Evaluate the following limits:

`lim_(x -> 0) (sqrt(2) - sqrt(1 + cosx))/(sin^2x)`


Choose the correct alternative:

`lim_(x - pi/2) (2x - pi)/cos x`


`lim_(x -> 5) |x - 5|/(x - 5)` = ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×