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Examine the continuity of the following: |x + 2| + |x – 1| - Mathematics

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प्रश्न

Examine the continuity of the following:

|x + 2| + |x – 1|

योग
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उत्तर

Let f(x) = |x + 2| + |x – 1|

f(x) is defined for all points of R.

Let x0 be an arbitrary point in R.

Then `lim_(x -> x_0)f(x) =  lim_(x -> x_0) (|x + 2| + |x - 1|)`

= `|x_0 + 2| + |x_0 - 1|`  .......(1)

`f(x_0) = |x_0+ 2| + |x_0 - 1|`  .......(2)

From equation (1) and (2) we get

`lim_(x -> x_0)f(x) =  f(x_0)`

Thus the limit of the function f(x) exist at x = x0 and is equal to the value of the function at x = x0.

Since x = x0 is an arbitrary point in R, the above
result is true for all points in R.

Hence f(x) is continuous at all points of R.

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Continuity
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.5 [पृष्ठ १२७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.5 | Q 2. (viii) | पृष्ठ १२७

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