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In problems 1 – 6, using the table estimate the value of the limitlimx→0cosx-1x x – 0.1 – 0.01 – 0.001 0.0001 0.01 0.1 f(x) 0.04995 0.0049999 0.0004999 – 0.0004999 – 0.004999 – 0.04995

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प्रश्न

In problems 1 – 6, using the table estimate the value of the limit
`lim_(x -> 0) (cos x - 1)/x`

x – 0.1  – 0.01 – 0.001 0.0001 0.01 0.1
f(x) 0.04995 0.0049999 0.0004999 – 0.0004999 – 0.004999 – 0.04995
सारिणी
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उत्तर

Let f(x) = `(cos x - 1)/x`

x – 0.1  – 0.01 – 0.001 0.0001 0.01 0.1
f(x)

`(cos(- 0.1) - 1)/(- 0.1)`

= `(cos(0.1) - 1)/(- 0.1)`

= `(- 0.00000152)/(- 0.1)`

= 0.00001

`(cos(- 0.01) - 1)/(- 0.01)`

= `(cos(0.01) - 1)/(- 0.01)`

= `(- 0.000001)/(- 0.01)`

= 0.00000015

`(cos(- 0.001) - 1)/(- 0.001)`

= `(cos(0.001) - 1)/(- 0.01)`

= `(- 0.0000)/(- 0.001)`

= 0.000

`(cos(0.001) - 1)/( 0.001)`

= `(cos(0.0001) - 1)/(- 0.001)`

= 0.000

`(cos(0.01) -1)/(0.01)`

= 0.000015

`(cos(0.1) -1)/(0.1)`

= 0.000000

`lim_(x -> 0) (cos x - 1)/x` = 0

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.1 [पृष्ठ ९५]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.1 | Q 6 | पृष्ठ ९५

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