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Evaluate the following limit : limx→1[x+x3+x5+...+x2n-1-nx-1] - Mathematics and Statistics

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प्रश्न

Evaluate the following limit :

`lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - "n")/(x - 1)]`

योग
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उत्तर

`lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - "n")/(x - 1)]`

= `lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - (1 + 1 + 1 + ...  "n times"))/(x - 1)]`

= `lim_(x -> 1)[((x - 1) + (x^3 - 1) + (x^5 - 1) + ... + (x^(2"n" - 1) - 1) ... ("n brackets"))/(x - 1)]`  

(∵ 1, 3, 5, …, 2n – 1 are the first n odd numbers)

= `lim_(x -> 1)[(x^1 - 1^1)/(x - 1) + (x^3 - 1^3)/(x - 1) + (x^5 - 1^5)/(x - 1) + ... + (x^(2"n" - 1) - 1^(2"n" - 1))/(x - 1)]`

= 1(1)0 + 3(1)2 + 5(1)4 + … + (2n – 1) (1)2n–2 

= 1 + 3 + 5 + ... + (2n – 1)

= `sum_("r" = 1)^"n"(2"r" - 1)`

= `2 sum_("r" = 1)^"n" "r" - sum_("r" = 1)^"n" 1`

= `2*("n"("n" + 1))/2 - "n"`

= n(n + 1) – n

= n2 + n – n

= n2

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Concept of Limits
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Limits - Exercise 7.1 [पृष्ठ १३९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
Exercise 7.1 | Q III. (9) | पृष्ठ १३९

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