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Examine the continuity of the following: x2 cos x - Mathematics

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प्रश्न

Examine the continuity of the following:

x2 cos x

योग
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उत्तर

Let f(x) = x2 cos x

f(x) is defined at all points of R.

Let x0 be an arbitrary point in R.

Then `lim_(x -> x_0) f(x) =  lim_(x -> x_0) x^2 cos x`

= x20 cos 0

f(x0) = x20 cos 0

From equation (1) and (2), we have

`lim_(x -> x_0) x^2 cos x = f(x_0)`

∴ The limit at x = x0 exist and is equal to the value of the function f(x) at x = x0.

Since x0 is arbitrary, the limit of the function exist and is equal to the value of the function for all points in R.

∴ f(x) satisfies all conditions for continuity.

Hence f (x) is a continuous function in R.

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Continuity
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Calculus - Limits and Continuity - Exercise 9.5 [पृष्ठ १२७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 9 Differential Calculus - Limits and Continuity
Exercise 9.5 | Q 2. (ii) | पृष्ठ १२७

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