#### Topics

##### Number Systems

##### Number Systems

##### Algebra

##### Polynomials

##### Linear Equations in Two Variables

##### Algebraic Expressions

##### Algebraic Identities

##### Coordinate Geometry

##### Geometry

##### Introduction to Euclid’S Geometry

##### Lines and Angles

##### Triangles

##### Quadrilaterals

- Concept of Quadrilaterals - Sides, Adjacent Sides, Opposite Sides, Angle, Adjacent Angles and Opposite Angles
- Angle Sum Property of a Quadrilateral
- Types of Quadrilaterals
- Another Condition for a Quadrilateral to Be a Parallelogram
- Theorem of Midpoints of Two Sides of a Triangle
- Property: The Opposite Sides of a Parallelogram Are of Equal Length.
- Theorem: A Diagonal of a Parallelogram Divides It into Two Congruent Triangles.
- Theorem : If Each Pair of Opposite Sides of a Quadrilateral is Equal, Then It is a Parallelogram.
- Property: The Opposite Angles of a Parallelogram Are of Equal Measure.
- Theorem: If in a Quadrilateral, Each Pair of Opposite Angles is Equal, Then It is a Parallelogram.
- Property: The diagonals of a parallelogram bisect each other. (at the point of their intersection)
- Theorem : If the Diagonals of a Quadrilateral Bisect Each Other, Then It is a Parallelogram

##### Area

##### Circles

- Concept of Circle - Centre, Radius, Diameter, Arc, Sector, Chord, Segment, Semicircle, Circumference, Interior and Exterior, Concentric Circles
- Angle Subtended by a Chord at a Point
- Perpendicular from the Centre to a Chord
- Circles Passing Through One, Two, Three Points
- Equal Chords and Their Distances from the Centre
- Angle Subtended by an Arc of a Circle
- Cyclic Quadrilateral

##### Constructions

##### Mensuration

##### Areas - Heron’S Formula

##### Surface Areas and Volumes

##### Statistics and Probability

##### Statistics

##### Probability

#### theorem

**The opposite sides of a parallelogram are of equal length.**

**Given:** ABCD is a parallelogram.

**To Prove:** AB = DC and BC = AD.

**Construction: **Draw any one diagonal, say `bar(AC)`.

**Proof: **

Consider a parallelogram ABCD,

In triangles ΔABC and ΔADC,

∠ 1 = ∠2, ∠ 3 = ∠ 4 .....(Pair of alternate angle)

and `bar(AC)` is common side.

Side AC = Side AC .....(common side)

∠ 1 ≅ ∠2 .....(Pair of alternate angle)

∠ 3 ≅ ∠ 4 .....(Pair of alternate angle)

by ASA congruency condition,

∆ ABC ≅ ∆ CDA

This gives AB = DC and BC = AD.

Hence Proved.

#### Example

Find the perimeter of the parallelogram PQRS.

In a parallelogram, the opposite sides have the same length.

Therefore, PQ = SR = 12 cm and QR = PS = 7 cm.

So,

Perimeter = PQ + QR + RS + SP

= 12 cm + 7 cm + 12 cm + 7 cm

= 38 cm.

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