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Cyclic Quadrilateral and Concyclic Points

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CISCE: Class 10

Theorem: Opposite angles of a cyclic quadrilateral are supplementary

Statement:
The sum of the opposite angles of a cyclic quadrilateral is 180°.

Short Proof (Idea):

  • Let ABCD be a cyclic quadrilateral.

  • Arc ABC subtends an angle ∠ADC at the circle and ∠AOC at the centre.

  • The angle at the centre is double the angle at the circle.

    ∠ADC=`1/2`∠AOC

  • Similarly, the other arc subtends:

    ∠ABC = `1/2`(reflex ∠AOC)

  • The sum of angles around the centre is 360°.

  • Therefore,

    ∠ADC + ∠ABC = `1/2`(360°) = 180

Conclusion:
Hence, the opposite angles of a cyclic quadrilateral are supplementary.

CISCE: Class 10

Theorem: Converse of Cyclic Quadrilateral

Statement:
If the sum of a pair of opposite angles of a quadrilateral is 180°, then the quadrilateral is cyclic.

Short Proof (Idea):

  • Given, ∠B + ∠D = 180°.

  • Draw a circle through three vertices of the quadrilateral.

  • If the fourth vertex does not lie on the circle, an exterior angle becomes equal to its interior opposite angle, which is not possible.

  • Hence, the fourth vertex must lie on the same circle.

Conclusion:
Therefore, ABCD is a cyclic quadrilateral.

CISCE: Class 10

Theorem: Exterior Angle of a Cyclic Quadrilateral

Statement:

The exterior angle of a cyclic quadrilateral is equal to the interior opposite angle.

Short Proof (Idea):

  • In a cyclic quadrilateral, the sum of opposite angles is 180°.

  • The exterior angle and the adjacent interior angle form a straight line, so their sum is 180°.

  • Since both are supplementary to the same angle, they are equal.

Conclusion:

Therefore, the exterior angle of a cyclic quadrilateral is equal to the interior opposite angle.

Shaalaa.com | Circles (Cyclic Properties Part 1)

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