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- Operations on Matrices>Scalar Multiplication
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Introduction
Scalar multiplication is a basic operation on matrices in which a single real number (scalar) multiplies every entry of a matrix.
This concept is used throughout higher mathematics, including systems of equations, transformations, and vector-space methods in physics and engineering.
Definition: Scalar Multiplication of a Matrix
Let \[A = [a_{ij}]_{m \times n}\] be a matrix and k be a real number (scalar).
Then the scalar multiple of A by k is the matrix kA defined as:
That is, each entry of A is multiplied by the scalar k.
Definition: Negative of a Matrix
The negative of a matrix A, denoted by -A, is defined as the scalar multiple \[-1 \cdot A\].
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So, if \[A = [a_{ij}]\], then \[-A = [-a_{ij}]\]
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Adding a matrix to its negative gives the zero matrix: A + (-A) = O
where O is the zero matrix of the same order as A.
Properties
| Property | Formula |
|---|---|
| Distributive over matrix addition | (k(A + B) = kA + kB) |
| Distributive over scalar addition | ((k + l)A = kA + lA) |
| Associative with respect to scalar multiplication | (k(lA) = (kl)A) |
| Multiplication by 1 | \[1 \cdot A = A\] |
| Multiplication by 0 | \[0 \cdot A = O\] |
| Negative scalar | (-1)A = -A |
Example 1
Find the values of x and y from the following equation:
\[2 \begin{bmatrix} x & 5 \\ 7 & y-3 \end{bmatrix}+ \begin{bmatrix} 3 & -4 \\ 1 & 2 \end{bmatrix}= \begin{bmatrix} 7 & 6 \\ 15 & 14 \end{bmatrix}\]
Solution We have
\[2 \begin{bmatrix} x & 5 \\ 7 & y-3 \end{bmatrix}+ \begin{bmatrix} 3 & -4 \\ 1 & 2 \end{bmatrix}= \begin{bmatrix} 7 & 6 \\ 15 & 14 \end{bmatrix}\Rightarrow \begin{bmatrix} 2x & 10 \\ 14 & 2y-6 \end{bmatrix}+ \begin{bmatrix} 3 & -4 \\ 1 & 2 \end{bmatrix}= \begin{bmatrix} 7 & 6 \\ 15 & 14 \end{bmatrix}\]
or \[\begin{bmatrix} 2x+3 & 10-4 \\ 14+1 & 2y-6+2 \end{bmatrix}= \begin{bmatrix} 7 & 6 \\ 15 & 14 \end{bmatrix}\Rightarrow \begin{bmatrix} 2x+3 & 6 \\ 15 & 2y-4 \end{bmatrix}= \begin{bmatrix} 7 & 6 \\ 15 & 14 \end{bmatrix}\]
or 2x + 3 = 7 and 2y – 4 = 14 (Why?)
or 2x = 7 – 3 and 2y = 18
or \[x=\frac{4}{2}\] and \[y=\frac{18}{2}\]
i.e. x = 2 and y = 9.
Key Points: Scalar Multiplication
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Scalar multiplication: \[kA = [ka_{ij}]\].
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Negative of a matrix: -A = (-1)A.
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Order of matrix does not change after scalar multiplication.
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k(A + B) = kA + kB.
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(k + l)A = kA + lA.
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k(lA) = (kl)A.
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\[0 \cdot A = O\], \[1 \cdot A = A\].
