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Evaluation of Definite Integrals by Substitution

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Estimated time: 6 minutes
CBSE: Class 12

Introduction

Integration by substitution is a method in which a suitable part of the integrand is replaced by a new variable so that the integral becomes easier to evaluate. In definite integrals, the limits must also be changed according to the new variable.

CBSE: Class 12

Method 1: Resubstitution

  • Ignore the integration limits initially and integrate the function using substitution (t = g(x)).

  • Find the antiderivative and resubstitute the new variable back into terms of the original variable x.

  • Evaluate the resulting expression using the original integration limits (a and b).

CBSE: Class 12

Method 2: Changing the Limits

  • Substitute a new variable, such as t = g(x), meaning \[dt = g'(x) \, dx\].

  • Change the limits of integration to match the new variable:

    • Lower limit becomes \[t_{lower} = g(a)\]

    • Upper limit becomes \[t_{upper} = g(b)\]

  • Integrate the new integrand with respect to t and evaluate it directly using the new limits—no need to substitute back to x.

CBSE: Class 12

Example 1

Substitution with Inverse Trigonometric Functions

Evaluate:

\[\int_{0}^{1} \frac{\tan^{-1}x}{1 + x^2} \, dx\]

Solution:

Let \[t = \tan^{-1}x\], then \[dt = \frac{1}{1 + x^2} \, dx\].

Update the limits:

  • When x = 0, \[t = \tan^{-1}(0) = 0\]
  • When x = 1, \[t = \tan^{-1}(1) = \frac{\pi}{4}\]

Substitute into the integral:

\[\int_{0}^{\frac{\pi}{4}} t \, dt = \left[ \frac{t^2}{2} \right]_{0}^{\frac{\pi}{4}}\]
\[= \frac{1}{2} \left[ \left(\frac{\pi}{4}\right)^2 - 0 \right] = \frac{1}{2} \left( \frac{\pi^2}{16} \right) = \frac{\pi^2}{32}\]
CBSE: Class 12

Key Points: Evaluation of Definite Integrals by Substitution

  • Look for an inner function and its derivative.

  • Choose substitution carefully.

  • Change the limits immediately.

  • Integrate in the new variable.

  • Do not add +C in a definite integral.

Shaalaa.com | Integrals part 40 (Definite integral by substitution)

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Integrals part 40 (Definite integral by substitution) [00:12:20]
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