Share
Notifications

View all notifications

Logarithmic Differentiation

Login
Create free account


      Forgot password?

notes

we will learn to differentiate certain special class of functions given in the form 
y = f(x) = `[u(x)]^(v (x))`
 By taking logarithm (to base e) the above may be rewritten as
log y = v(x) log [u(x)]

Using chain rule we may differentiate this to get
`1/y . (dy)/(dx) = v(x) . 1/(u(x)) . u'(x) +v'(x) . log [u(x)]`

which implies that
`(dy)/(dx) = y [(v(x))/(u(x)) . u'(x) + v'(x) . log[u(x)]]`

The main point to be noted in this method is that f(x) and u(x) must always be positive as otherwise their logarithms are not defined. This process of differentiation is known as logarithms differentiation. 

Video Tutorials

We have provided more than 1 series of video tutorials for some topics to help you get a better understanding of the topic.

Series 1


Series 2


Series 3


Shaalaa.com | Logarithmic Differentiation (example1)

Shaalaa.com


Next video


Shaalaa.com


Logarithmic Differentiation (example1) [00:08:15]
S
Series 1: playing of 2
1
0%


S
View in app×