#### notes

Consider the polynomial `p(x) = 5x^3 – 2x^2 + 3x – 2`.

If we replace x by 1 everywhere in p(x), we get

`p(1) = 5 × (1)^3 – 2 × (1)^2 + 3 × (1) – 2`

= 5 – 2 + 3 –2

= 4

So, we say that the value of p(x) at x = 1 is 4.

Similarly, the polynomial p(x) = x – 1.

p(1) = 1 – 1 = 0. As p(1) = 0, we say that 1 is a zero of the polynomial p(x).

A non-zero constant polynomial has no zero. Every real number is a zero of the zero polynomial.

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