Advertisements
Advertisements
Question
If `x = −1/2` is a zero of the polynomial `p(x)=8x^3-ax^2 -+2` find the value of a.
Advertisements
Solution
we have `p(x)=8x^2-ax^2-x=2`
put `x=-1/2`
`⇒p(-1/2)=8xx(-1/2)^3-ax(-1/2)^2-(-1/2)+2`
`=8xx-^1/8-axx1/4+1/2+2`
`=-1-a/4+1/2+2`
`=3/2-a/4`
giventhat `x=(-1)/2`is a root of p(x)
`⇒ p(-1/2) = 0`
`∴ 3/2 - a/4 = 0 ⇒ a/4=3/2⇒a=3/2xx4^2`
`⇒a=6`
APPEARS IN
RELATED QUESTIONS
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = (x + 1) (x – 2), x = – 1, 2
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = lx + m, `x = – m/l`
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`f ( x ) = 3x +1, x = - 1/3`
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`g(x)=3x^2-2,` `x=2/sqrt3 2/sqrt3`
Find the zero of the polynomial of the following:
q(y) = 2y – 3
Verify whether the following are zeros of the polynomial indicated against them, or not
p(x) = 2x − 1, x = `1/2`
Find the number of zeros of the following polynomial represented by their graph
Find p(0), p(1), p(–2) for the following polynomial:
p(y) = (y + 2)(y – 2)
0 and 2 are the zeroes of t2 – 2t
Find the zeroes of the polynomial in the following:
p(x) = x – 4
