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Question
Find the zeroes of the polynomial:
p(x) = (x – 2)2 – (x + 2)2
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Solution
p(x) = (x – 2)2 − (x + 2)2
We know that,
Zero of the polynomial p(x) = 0
Hence, we get,
⇒ (x – 2)2 − (x + 2)2 = 0
Expanding using the identity, a2 – b2 = (a – b)(a + b)
⇒ (x – 2 + x + 2)(x – 2 – x – 2) = 0
⇒ 2x(– 4) = 0
⇒ – 8x = 0
Therefore, the zero of the polynomial = 0
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