Advertisements
Advertisements
प्रश्न
Find the zeroes of the polynomial:
p(x) = (x – 2)2 – (x + 2)2
Advertisements
उत्तर
p(x) = (x – 2)2 − (x + 2)2
We know that,
Zero of the polynomial p(x) = 0
Hence, we get,
⇒ (x – 2)2 − (x + 2)2 = 0
Expanding using the identity, a2 – b2 = (a – b)(a + b)
⇒ (x – 2 + x + 2)(x – 2 – x – 2) = 0
⇒ 2x(– 4) = 0
⇒ – 8x = 0
Therefore, the zero of the polynomial = 0
APPEARS IN
संबंधित प्रश्न
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = 3x2 – 1, x = `-1/sqrt3,2/sqrt3`
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`f(x) = lx + m , x = - m/1`
Find the zero of the polynomial of the following:
q(y) = 2y – 3
Find the zero of the polynomial in the following:
h(x) = ax + b, a ≠ 0, a, b ∈ R
Verify whether the following are zeros of the polynomial, indicated against them, or not
p(x) = ax + b, x = `(-"b")/"a"`
Find the number of zeros of the following polynomial represented by their graph
Find the number of zeros of the following polynomial represented by their graph
Find the number of zeros of the following polynomial represented by their graph
If p(x) = x + 3, then p(x) + p(–x) is equal to ______.
`-1/3` is a zero of 3x + 1
