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प्रश्न
Find the zeroes of the polynomial:
p(x) = (x – 2)2 – (x + 2)2
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उत्तर
p(x) = (x – 2)2 − (x + 2)2
We know that,
Zero of the polynomial p(x) = 0
Hence, we get,
⇒ (x – 2)2 − (x + 2)2 = 0
Expanding using the identity, a2 – b2 = (a – b)(a + b)
⇒ (x – 2 + x + 2)(x – 2 – x – 2) = 0
⇒ 2x(– 4) = 0
⇒ – 8x = 0
Therefore, the zero of the polynomial = 0
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संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(x) = (x – 1) (x + 1)
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = x2, x = 0
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`f ( x ) = 3x +1, x = - 1/3`
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`f (x) = 2x +1, x = 1/2`
Find the zero of the polynomial of the following :
f(z) = 8z
Find the number of zeros of the following polynomial represented by their graph

If p(x) = x + 3, then p(x) + p(–x) is equal to ______.
Zero of a polynomial is always 0
`-1/3` is a zero of 3x + 1
0 and 2 are the zeroes of t2 – 2t
