Advertisements
Advertisements
प्रश्न
Find the zeroes of the polynomial:
p(x) = (x – 2)2 – (x + 2)2
Advertisements
उत्तर
p(x) = (x – 2)2 − (x + 2)2
We know that,
Zero of the polynomial p(x) = 0
Hence, we get,
⇒ (x – 2)2 − (x + 2)2 = 0
Expanding using the identity, a2 – b2 = (a – b)(a + b)
⇒ (x – 2 + x + 2)(x – 2 – x – 2) = 0
⇒ 2x(– 4) = 0
⇒ – 8x = 0
Therefore, the zero of the polynomial = 0
APPEARS IN
संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(x) = (x – 1) (x + 1)
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = 3x2 – 1, x = `-1/sqrt3,2/sqrt3`
Find the zero of the polynomial in the following case:
p(x) = 2x + 5
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`f ( x ) = 3x +1, x = - 1/3`
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`f ( x) = x^2and x = 0`
Find the value of the polynomial 5x – 4x2 + 3 at x = 2.
Find the number of zeros of the following polynomial represented by their graph
A polynomial cannot have more than one zero
Find p(0), p(1), p(–2) for the following polynomial:
p(x) = 10x – 4x2 – 3
Find the zeroes of the polynomial in the following:
h(y) = 2y
