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Question
Find p(0), p(1) and p(2) for the following polynomial:-
p(t) = 2 + t + 2t2 – t3
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Solution
p(t) = 2 + t + 2t2 – t3
p(0) = 2 + 0 + 2(0)2 – (0)3
= 2 + 0 + 0 – 0 = 2
p(1) = 2 + 1 + 2(1)2 – (1)3
= 2 + 1 + 2 – 1 = 4
p(2) = 2 + 2 + 2(2)2 – (2)3
= 2 + 2 + 8 – 8 = 4
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