Advertisements
Advertisements
Question
Find p(0), p(1) and p(2) for the following polynomial:-
p(y) = y2 – y + 1
Advertisements
Solution
p(y) = y2 − y + 1
p(0) = (0)2 − 0 + 1 = 0 − 0 + 1 = 1
p(1) = (1)2 − 1 + 1 = 1 − 1 + 1 = 1
p(2) = (2)2 − 2 + 1 = 4 − 2 + 1 = 3
APPEARS IN
RELATED QUESTIONS
Find p(0), p(1) and p(2) for the following polynomial:-
p(t) = 2 + t + 2t2 – t3
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = x2 – 1, x = 1, –1
Verify whether the following are zeros of the polynomial indicated against them, or not
p(x) = 2x − 1, x = `1/2`
Find the number of zeros of the following polynomial represented by their graph
Find the number of zeros of the following polynomial represented by their graph
One of the zeroes of the polynomial 2x2 + 7x – 4 is ______.
Zero of a polynomial is always 0
`-1/3` is a zero of 3x + 1
`(-4)/5` is a zero of 4 – 5y
Find the zeroes of the polynomial in the following:
p(x) = x – 4
