Advertisements
Advertisements
प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(y) = y2 – y + 1
Advertisements
उत्तर
p(y) = y2 − y + 1
p(0) = (0)2 − 0 + 1 = 0 − 0 + 1 = 1
p(1) = (1)2 − 1 + 1 = 1 − 1 + 1 = 1
p(2) = (2)2 − 2 + 1 = 4 − 2 + 1 = 3
APPEARS IN
संबंधित प्रश्न
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = lx + m, `x = – m/l`
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = 3x2 – 1, x = `-1/sqrt3,2/sqrt3`
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = 2x + 1, `x = 1/2`
Find the zero of the polynomial in the following case:
p(x) = 3x – 2
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`g(x)=3x^2-2,` `x=2/sqrt3 2/sqrt3`
Find the zero of the polynomial of the following:
p(x) = ax when a ≠ 0
Find the number of zeros of the following polynomial represented by their graph
If p(x) = x + 3, then p(x) + p(–x) is equal to ______.
0 and 2 are the zeroes of t2 – 2t
–3 is a zero of y2 + y – 6
