Advertisements
Advertisements
प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(t) = 2 + t + 2t2 – t3
Advertisements
उत्तर
p(t) = 2 + t + 2t2 – t3
p(0) = 2 + 0 + 2(0)2 – (0)3
= 2 + 0 + 0 – 0 = 2
p(1) = 2 + 1 + 2(1)2 – (1)3
= 2 + 1 + 2 – 1 = 4
p(2) = 2 + 2 + 2(2)2 – (2)3
= 2 + 2 + 8 – 8 = 4
APPEARS IN
संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(x) = (x – 1) (x + 1)
Find the zero of the polynomial in the following case:
p(x) = 2x + 5
Find the zero of the polynomial in the following case:
p(x) = 3x
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`f (x) = 2x +1, x = 1/2`
Find the number of zeros of the following polynomial represented by their graph

Find the number of zeros of the following polynomial represented by their graph

If `p(x) = x^2 - 2sqrt(2)x + 1`, then `p(2sqrt(2))` is equal to ______.
One of the zeroes of the polynomial 2x2 + 7x – 4 is ______.
–3 is a zero of x – 3
–3 is a zero of y2 + y – 6
