Advertisements
Advertisements
प्रश्न
Find the zero of the polynomial of the following:
p(x) = 2x + 5
Advertisements
उत्तर
p(x) = 2x + 5
= `2(x + 5/2)`
`"p"(-5/2) = 2(- 5/2) + 5/2`
= −5 + 5
= 2(0)
= 0
Here `-5/2` is the zero of p(x).
APPEARS IN
संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(y) = y2 – y + 1
Find p(0), p(1) and p(2) for the following polynomial:-
p(t) = 2 + t + 2t2 – t3
Verify whether the following zeroes of the polynomial, indicated against them.
`p(x) = 3x + 1, x = -1/3`
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = x2 – 1, x = 1, –1
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = (x + 1) (x – 2), x = – 1, 2
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = 3x2 – 1, x = `-1/sqrt3,2/sqrt3`
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = 2x + 1, `x = 1/2`
Find the zero of the polynomial in the following case:
p(x) = 2x + 5
Find the zero of the polynomial in the following case:
p(x) = cx + d, c ≠ 0, c, d are real numbers.
Find the value of the polynomial 5x – 4x2 + 3 at x = –1.
Find the zero of the polynomial of the following :
f(z) = 8z
Find the zero of the polynomial of the following:
p(x) = ax when a ≠ 0
Verify whether the following are zeros of the polynomial indicated against them, or not
p(x) = 2x − 1, x = `1/2`
Find the number of zeros of the following polynomial represented by their graph
Find the number of zeros of the following polynomial represented by their graph
Zeros of (2 – 3x) is ___________
If `p(x) = x^2 - 2sqrt(2)x + 1`, then `p(2sqrt(2))` is equal to ______.
Zero of the zero polynomial is ______.
Zero of the polynomial p(x) = 2x + 5 is ______.
Zero of a polynomial is always 0
Find p(0), p(1), p(–2) for the following polynomial:
p(y) = (y + 2)(y – 2)
–3 is a zero of x – 3
–3 is a zero of y2 + y – 6
Find the zeroes of the polynomial in the following:
p(x) = x – 4
Find the zeroes of the polynomial in the following:
h(y) = 2y
