Advertisements
Advertisements
प्रश्न
Find p(0), p(1), p(–2) for the following polynomial:
p(y) = (y + 2)(y – 2)
Advertisements
उत्तर
Consider the polynomial:
p(y) = (y + 2)(y – 2)
The value of given polynomial at y = 0 is
p(0) = (0 + 2)(0 – 2)
= 2 × –2
= – 4
When y = 1
p(1) = (1 + 2)(1 – 2)
= 3 × –1
= 3
When y = –2
p(1) = (–2 + 2)(–2 – 2)
= 0 × (–2 – 2)
= 0
APPEARS IN
संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(t) = 2 + t + 2t2 – t3
Find the zero of the polynomial in the following case:
p(x) = x – 5
Find the zero of the polynomial in the following case:
p(x) = ax, a ≠ 0
Verify whether the indicated numbers is zeroes of the polynomials corresponding to them in the following case:
`g(x)=3x^2-2,` `x=2/sqrt3 2/sqrt3`
Find the zero of the polynomial of the following:
p(x) = 2x + 5
Find the zero of the polynomial of the following:
p(x) = ax when a ≠ 0
Find the zero of the polynomial in the following:
h(x) = ax + b, a ≠ 0, a, b ∈ R
Verify whether the following are zeros of the polynomial, indicated against them, or not
p(x) = ax + b, x = `(-"b")/"a"`
Find the number of zeros of the following polynomial represented by their graph
Zeros of (2 – 3x) is ___________
