Advertisements
Advertisements
प्रश्न
Find p(0), p(1), p(–2) for the following polynomial:
p(y) = (y + 2)(y – 2)
Advertisements
उत्तर
Consider the polynomial:
p(y) = (y + 2)(y – 2)
The value of given polynomial at y = 0 is
p(0) = (0 + 2)(0 – 2)
= 2 × –2
= – 4
When y = 1
p(1) = (1 + 2)(1 – 2)
= 3 × –1
= 3
When y = –2
p(1) = (–2 + 2)(–2 – 2)
= 0 × (–2 – 2)
= 0
APPEARS IN
संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(y) = y2 – y + 1
Verify whether the following zeroes of the polynomial are indicated against them.
p(x) = 5x – π, `x = 4/5`
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = x2, x = 0
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = 2x + 1, `x = 1/2`
Find the zero of the polynomial in the following case:
p(x) = ax, a ≠ 0
Find the zero of the polynomial in the following case:
p(x) = cx + d, c ≠ 0, c, d are real numbers.
Find the number of zeros of the following polynomial represented by their graph
The zero of the polynomial 2x + 5 is
–3 is a zero of x – 3
0 and 2 are the zeroes of t2 – 2t
