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Question
Find p(0), p(1), p(–2) for the following polynomial:
p(y) = (y + 2)(y – 2)
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Solution
Consider the polynomial:
p(y) = (y + 2)(y – 2)
The value of given polynomial at y = 0 is
p(0) = (0 + 2)(0 – 2)
= 2 × –2
= – 4
When y = 1
p(1) = (1 + 2)(1 – 2)
= 3 × –1
= 3
When y = –2
p(1) = (–2 + 2)(–2 – 2)
= 0 × (–2 – 2)
= 0
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