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Methods of Integration>Integration Using Trigonometric Identities

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Estimated time: 7 minutes
CBSE: Class 12

Definition: Integration using Trigonometric Identities

Integration using trigonometric identities means converting a trigonometric expression into an easier form with the help of standard identities before integrating.

CBSE: Class 12

Identities

Identity Use
\(\cos 2x = 2\cos^2 x - 1\)  For \(\cos^2 x\)
\(\cos^2 x = \frac{1+\cos 2x}{2}\) For even power of cosine
\(\sin A \cos B = \frac{1}{2}[\sin(A+B)+\sin(A-B)]\) For product of sine and cosine
\(\sin 3x = 3\sin x - 4\sin^3 x\) For \(\sin^3 x\)
CBSE: Class 12

Example 1

Find

  1. \[\int \cos^2 x dx\]
  2. \[\int \sin 2x \cos 3x dx\]

Solution:

(i) Recall the identity \[\cos 2x = 2 \cos^2 x - 1\], which gives

\[\cos^2 x = \frac{1 + \cos 2x}{2}\]

Therefore, \[\int \cos^2 x dx = \frac{1}{2} \int (1 + \cos 2x) dx\]

\[= \frac{1}{2} \int dx + \frac{1}{2} \int \cos 2x dx\]

\[= \frac{x}{2} + \frac{1}{4} \sin 2x + \text{C}\]

(ii) Recall the identity \[\sin x \cos y = \frac{1}{2} [\sin (x + y) + \sin (x - y)]\]  

Then \[\int \sin 2x \cos 3x dx = \frac{1}{2} \left[ \int \sin 5x dx - \int \sin x dx \right]\]

\[= \frac{1}{2} \left[ -\frac{1}{5} \cos 5x + \cos x \right] + \text{C}\]

\[= -\frac{1}{10} \cos 5x + \frac{1}{2} \cos x + \text{C}\]

CBSE: Class 12

Key Points: Integration Using Trigonometric Identities

  • First inspect the pattern in the integrand.

  • Do not integrate complicated trigonometric expressions directly if an identity can simplify them first.

  • After simplification, integrate term by term carefully.

  • Always add the constant of integration, \(C\).

Shaalaa.com | Integrals part 17 (Integration by trigonometric identities)

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Integrals part 17 (Integration by trigonometric identities) [00:11:55]
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